Java编程:鼠标监听器问题

时间:2014-10-27 20:29:04

标签: java swing mouse-listeners

我遇到了mouselistener的问题。我一直试图在最后一小时解决这个问题,找到任何相关的教程,但它们都是一样的,不是把它添加到jpanel,但是我没有jpanel!

ClientApplicationWindow类:

public final void createClientWindow(int height, int width) {
        ClientApplicationWindow clientApplicationWindow = new ClientApplicationWindow();
        MouseEventHandler mouseEventHandler = new MouseEventHandler();
        this.addMouseListener(mouseEventHandler);
        frame.setTitle(Constants.CLIENT_NAME);
        frame.setSize(width, height);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.add(clientApplicationWindow);
        frame.setLocationRelativeTo(null);
        frame.setFocusable(true);
        frame.setResizable(false);
        frame.addWindowListener(new WindowAdapter() {
            public void windowClosing(WindowEvent e) {

            }
        });
        loadIcon();
        loadCursor();
        frame.setVisible(true);
        clientApplicationWindow.start();
    }

MouseEventHandler类:

@Override
public void mouseClicked(MouseEvent e) {
    System.out.println("Mouse Clicked X: "+e.getX()+" - Mouse Clicked Y: "+e.getY());
}

谢谢!

1 个答案:

答案 0 :(得分:3)

没有更多证据,这看起来很糟糕......

ClientApplicationWindow clientApplicationWindow = new ClientApplicationWindow();
MouseEventHandler mouseEventHandler = new MouseEventHandler();
this.addMouseListener(mouseEventHandler);
//...
frame.add(clientApplicationWindow);

假设createClientWindow实际上在ClientApplicationWindow类中,您正在创建ClientApplicationWindow的新实例,并将MouseListener添加到当前实例(this })并将新实例添加到框架中......

这表明this没有附加到可显示的容器上,因此在屏幕上看不到...所以它无法接收鼠标事件......

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