如何使用C ++将一系列整数转换为列表

Question

我有一个格式为1,3-7,10,11-15的字符串输入 我想识别范围内输入的所有整数。我如何使用C ++实现这一目标？

TIA 顾比

Answer 1

此问题属于解析域。你会使用解析器。解析器解释一种语言。在您的情况下，语言将如下所示：

input = comma-separated sequence of fragments
fragment = integer or range
range = integer-integer
integer = sequence of digits 0..9

Answer 2

//Disclaimer -- untested
//Disclaimer -- this is not good code, but it's a quick and dirty way to do this
//              if you're trying to see a possible solution.

#include <algorithm>
#include <functional>
#include <vector>

const char input[] = "1,3-7,10,11-15";
const char * inputBegin = input;
const char * inputEnd = input + strlen(input);
std::vector<int> result;
for(; inputBegin < inputEnd; inputBegin = std::find_if(inputBegin, inputEnd, isdigit)) {
    int first = *inputBegin - '0';
    for(inputBegin++; inputBegin < inputEnd && isdigit(*inputBegin); inputBegin++)
        first = first * 10 + (*inputBegin - '0');
    int last = first;
    if (++inputBegin < inputEnd && *inputBegin == '-') {
        last = inputBegin - '0';
        for(inputBegin++; inputBegin < inputEnd && isdigit(*inputBegin); inputBegin++)
            last = last * 10 + (*inputBegin - '0');
    }
    for(; first < last; first++)
        result.push_back(first);
}