Question

我有以下任务：

在本章中，您看到了一个如何编写确定是否的算法的示例数字是偶数还是奇数。编写一个生成100个随机数的程序，然后保留这些随机数中有多少是偶数，有多少是奇数。

这是我能够获得多少，我可以获得100个数字，但我无法弄清楚如何总结奇数和平均数。这应该包括一个返回布尔函数的值。

我们被允许使用的是循环，if-elif-else，函数和其他基本内容。

import random

NUMBER_LIST = [random.randint(0,1000)]

def main():

    for numbers in range(100):

        number = print(NUMBER_LIST)
        number

    is_even(number)

    print('The total amount of even numbers is', even_count)
    print('The total amount of odd numbers is', 100 - even_count)   

def is_even(number):

    even_count = 0

    for number in NUMBERS_LIST:
        if (number % 2):
            even_count += 1

    return even_count

main()

编辑：我不应该使用List，所以如果没有这样做，请告诉我！

Answer 1

import random

def main():
    numberList = []  # create an empty list, to add 100 random ints to
    for i in range(100):
        numberList.append(random.randint(1,1000))  # add a random int

    # now, numberList has 100 random numbers in it

    # keep track of how many odd numbers
    oddCount = 0

    # loop through numberList
    for number in numberList:
        if number%2 == 1:  # number is odd
            oddCount += 1

    evenCount = 100 - oddCount  # if a number is not odd, it is not even

    print("There are", oddCount, "odd numbers, and", evenCount, "even numbers")

好的，现在我们已经拥有了这个硬编码版本，让我们尝试一种更灵活的方式，让您尽可能多地指定：

def main(numNumbers, smallestNumber, biggestNumber):
    numberList = []
    for i in range(numNumbers):
        numberList.append(random.randint(smallestNumber, biggestNumber))
    oddCount = 0
    for number in numberList:
        if number%2:  # oh look, I didn't have to do the `== 1` part
            oddCount += 1
    evenCount = numNumbers - oddCount
    print("There are", oddCount, "odd numbers, and", evenCount, "even numbers")

Answer 2

import random

NUMBER_LIST = [random.randint(0,1000)]
even = 0;
odd = 0;
for numbers in range(100):
    if (numbers%2 == 1):
        odd = odd+1
    if (numbers%2 == 0):
        even = even+1
print('number of evens is: ',even)
print('number of odds is: ',odd)

所以你可以这样做。

Answer 3

您可以在没有列表的情况下执行此操作，但我们可以这样做，因为您的问题可能需要这样做。

首先，请注意您的代码只是创建一个列表，其中包含一个随机数。如果要使用100个随机数填充列表，则必须执行与此类似的操作：

NUMBER_LIST = []
i = 0
while i < 100:
    number = random.randint(0, 1000)
    NUMBER_LIST.append(number)
    i += 1

然后，检查数字是否为偶数，number % 2 == 0（即，数字除以2的余数为0，这将返回true或false）并递增相应的计数器：< / p>

NUMBER_LIST = []
# initialize both counters
evens = 0
odds = 0
i = 0
while i < 100:
    number = random.randint(0, 1000)
    NUMBER_LIST.append(number)
    if number % 2 == 0:
        evens += 1
    else:
        odds += 1
    i += 1

然后，您只需要打印计数：

print("The number of even numbers is: " + evens)
print("The number of odd numbers is: " + odds)

完整的代码将是：

import random
NUMBER_LIST = []
evens = 0
odds = 0
i = 0
while i < 100:
    number = random.randint(0, 1000)
    NUMBER_LIST.append(number)
    if number % 2 == 0:
        evens += 1
    else:
        odds += 1
    i += 1
print("The numbers were: " + str(NUMBER_LIST))
print("The number of even numbers is: " + evens)
print("The number of odd numbers is: " + odds)

没有清单：

import random
evens = 0
odds = 0
i = 0
while i < 100:
    number = random.randint(0, 1000)
    if number % 2 == 0:
        evens += 1
    else:
        odds += 1
    i += 1
print("The number of even numbers is: " + evens)
print("The number of odd numbers is: " + odds)

Answer 4

#!/usr/bin/env python3

import random
def main(n=100):
    NUMBER_LIST = [random.randint(0,1000) for x in range(0,n)]
    odds = len(list(filter(lambda x: x % 2, NUMBER_LIST)))
    print("Odd Numbers: {}\nEven Numbers: {}".format(odds, n-odds))

if __name__ == "__main__":
    main()

Answer 5

from random import randrange

even = 0
for i in range(100):
    num = randrange(1000)
    if num % 2 == 0:
        even += 1

print('There were {0} even numbers and {1} odd numbers.'.format(even, 100-even))

Answer 6

I am in the same class! This code worked for me.

import random

def main ():

    counter = 1
    even_numbers = 0
    odd_numbers = 0
    while counter < 101:

        a = random.randint(1,100)


        if a % 2 == 0:
            even_numbers += 1
        else:
            odd_numbers += 1
        counter += 1

    if counter == 101 :
        reveal_total(even_numbers, odd_numbers)

def reveal_total(even_numbers, odd_numbers):
    print("This many evens : ", even_numbers)
    print("This many odds : ", odd_numbers)

main()

带有奇数和偶数计数器的100个随机数

6 个答案: