我希望报告第5列没有重复值。所以我在下面的代码中使用了OrderedDict:
from collections import OrderedDict
with open(notmatch) as infile, open (two, 'w') as outfile:
reader = csv.reader(infile, delimiter='\t')
writer = csv.writer(outfile, delimiter='\t')
for gg, poss, codee, ref, alt, *rest in reader:
gg = int (gg)
poss = int(poss)
cls = ref + alt
clss = list(OrderedDict.fromkeys(cls))
writer.writerow([gg, poss, codee, d[gg][poss-1], clss] + rest)
这给了我第5列的输出。“clss”如下:
['A','B','C']
['G','A','T']
['G','A']
['T']
我想要的输出是:
A,B,C
G,A,T
G,A
T
我应该做出哪些改变以获得上述输出(没有括号和撇号)?请帮帮我!
答案 0 :(得分:1)
我希望这会有所帮助:
for l in [['A','B','C'],['G','A','T'],['G','A'],['T']]:
print ",".join(l)
输出:
A,B,C
G,A,T
G,A
T
我相信你的代码看起来像:
for l in [[gg, poss, codee, d[gg][poss-1], clss] + rest]:
writer.writerow(",".join(l) )