Question

如果这些特殊字符坚持单词，如何在Python中创建RE以在这些特殊字符,?!前添加空白？

这是输入字符串：

myString= 'I like him, but is he good? Maybe he is good , smart, and strong.'

所需的输出（如果特殊字符没有粘贴到某个单词，则不会被修改）：

modifiedString= 'I like him , but is he good ? Maybe he is good , smart , and strong.'

我试过这个：

modifiedString= re.sub('\w,' , ' ,' ,myString)

但它给出了错误的结果。它删除昏迷前的最后一个字符，这里是结果示例：

modifiedString = 'I like hi , but is he good? Maybe he is goo , smar , and strong.'

有任何解决这个问题的建议吗？

Answer 1

您可以使用re.sub：

>>> import re
>>> myString= 'I like him, but is he good? Maybe he is good , smart, and strong.'
>>> re.sub('(?<=\w)([!?,])', r' \1', myString)
'I like him , but is he good ? Maybe he is good , smart , and strong.'
>>>

(?<=\w)是一个与单词字符匹配的回顾断言。

([!?,])是一个匹配字符集[!?,]的捕获组（您可以在方括号内添加任何您想要匹配的字符）。

\1是指([!?,])抓取的文字。

Answer 2

事情是你也在替换角色。您需要在regex中使用组保留它，然后在替换字符串中指定组号。

>>> myString = 'I like him, but is he good? Maybe he is good , smart, and strong.'
>>> re.sub(r'(\w)([,?!])' , r'\1 \2' ,myString)
'I like him , but is he good ? Maybe he is good , smart , and strong.'

Answer 3

作为替代答案，您可以在没有正则表达式的情况下解决问题，只需使用str.replace：

>>> rep_list=['?',',','!']
>>> for i in rep_list : 
...  if i in myString:
...   myString=myString.replace(i,' '+i)
... 
>>> myString
'I like him , but is he good ? Maybe he is good  , smart , and strong.'

在特殊字符前面添加空格

3 个答案: