Question

我只是粘贴了我的示例输入＆amp;输出

示例输入：

Array
(
    [0] => Array
        (
            [id] => 1
            [msisdn] => 10
            [sc] => 8155
        )

    [1] => Array
        (
            [id] => 2
            [msisdn] => 20
            [sc] => 22020
        )

    [2] => Array
        (
            [id] => 3
            [msisdn] => 10
            [sc] => 8155
        )

    [3] => Array
        (
            [id] => 4
            [msisdn] => 10
            [sc] => 8155
        )

    [4] => Array
        (
            [id] => 5
            [msisdn] => 20
            [sc] => 22020
        )

    [5] => Array
        (
            [id] => 6
            [msisdn] => 30
            [sc] => 22020
        )

)

示例输出：

Array
(
    [0] => Array
        (
            [id] => 1,3,4
            [msisdn] => 10
            [sc] => 8155
        )

    [1] => Array
        (
            [id] => 2,5
            [msisdn] => 20
            [sc] => 22020
        )

    [2] => Array
        (
            [id] => 6
            [msisdn] => 30
            [sc] => 8155
        )

)

Answer 1

只需将该特定值设为键，然后在已经推送/存在时连接：

$new_array = array();
foreach ($array as $value) {
    if(!isset($new_array[$value['msisdn']])) {
        // if not yet pushed, just initialize
        $new_array[$value['msisdn']] = $value;
    } else {
        // if already inside, then just concatenate
        $new_array[$value['msisdn']]['id'] .= ', ' . $value['id'];
    }
}

$new_array = array_values($new_array);
echo '<pre>';
print_r($new_array);

Sample Output

Answer 2

在键盘上生活：http://codepad.org/0fw9k2w9

您可以使用PHP数组中的哈希映射这一事实。通过创建一个中间数组，您可以在O（n）时间内解决这个问题。

$merged = array();

foreach($array as $v) {
    $merged[$v['msisdn']][$v['sc']] [] = $v['id'];
}


$final = array();
foreach($merged as $msisdn=>$v) {
   foreach($v as $sc=>$ids) {
       $final [] = array('msisdn'=>$msisdn,'sc'=>$sc,'id'=>$ids);
   }
}

如果值与另一个索引相同，如何合并数组索引？

2 个答案: