Question

在yii2中，如何将多个相关记录保存到单个保存调用和单个事务中。我有两张桌子：

User - id, name
UserAddress - id , user_id , city

用户表与UserAdress表有一对多的关系

我想做的是：

UserAddress ua = new UserAddress();
ua.city = "fff"

User u = new User();
u.name = "test";
u.userAddress = new Array(ua);
u.save();

调用save on user应该保存user和useraddress，user_id也设置为user.id

Answer 1

 // You need create hasMany relation 'userAddress' (look guide relations)

$transaction = Yii::$app->db->beginTransaction();

try {

    $user = new User();
    $user->name = 'Name';
    $user->save();

    $ua = new UserAddress();
    $ua->city = 'City';

    $user->link('userAddress', $ua); // <-- it creates new record in UserAddress table with ua.user_id = user.id

    $transaction->commit();

} catch (Exception $e) {

    $transaction->rollBack();

}

Answer 2

除了之前的回答，我提出的变体在没有预先定义的关系和明确处理验证错误的情况下有效。

Yii::$app->db->transaction(function(){

    $user = new User();
    $user->name = 'Name';

    if( !$user->save() ){
        throw new Exception('Can\'t be saved user model. Errors: '. join(', ', $user->getFirstErrors()));
    }

    $userAddress = new UserAddress();
    $userAddress->city      = 'City';
    $userAddress->user_id   = $user->id;

    if( !$userAddress->save() ){
        throw new Exception('Can\'t be saved user address model. Errors: '. join(', ', $userAddress->getFirstErrors()));
    }

});

此代码严格确保将保存两个记录。如果某个模型无法保存，则会因验证错误而抛出异常。

Yii2在单个事务中保存单个保存调用中的相关记录

2 个答案: