Question

如何继续询问用户？

while(y != 0)
{
    d=y%10;
    z=z+(d*d*d);
    y=y/10;
}

如果是真或假：

switch ( z == x )
{
case true :cout <<x <<" is an Armstrong Number" << endl;
break ;
case false :cout <<x << " is not an Armstrong Number"<<endl;
}

输出如下：

请输入一个号码以检查它是否为阿姆斯壮号码：371
371 是阿姆斯特朗号码你想继续吗（是/否）？ N
再见！

如果写'Y＆＃39;它会继续在同一个问题上。

我工作：

while (y != 0)
{
    d=y%10;
    z=z+(d*d*d);
    y=y/10;
}
if ( z == x )
{
 cout <<x <<" is an Armstrong Number" << endl;
}
if ( z != x )
{
cout <<x << " is not an Armstrong Number"<<endl;
}

cout << "Do you want to continue (Y/N) ? " ;
    cin >> m;
    do{
    cout <<"Please enter a number to check if it is an Armstrong number:";
cin >> x;
    if ( z == x )
{
 cout <<x <<" is an Armstrong Number" << endl;
}
if ( z != x )
{
cout <<x << " is not an Armstrong Number"<<endl;
}
cout << "Do you want to continue (Y/N) ? " ;
    cin >> m;
    }while ( m == 'Y' || m == 'y') ;

 cout << "Bye"<<endl;

但是错了！

Answer 1

声明变量后，启动do-while循环：do{。在询问用户是否要继续或不关闭它的部分之后，如}while(ans == 'Y');其中'ans'是存储用户答案（Y / N）的char变量。像这样：

        //Here are the declared variables.
   do{
      cout << "Please enter a number to check if it is an Armstrong number: ";
      cin >> number; //Replace 'number' with the variable name you have used to store that number.
      //The algorithm, which tests if the number is Armstrong number or not, goes here.
      cout << "Do you want to continue (Y/N)? ";
      cin >> ans;
      }while(ans == 'Y');
      cout << "Bye";

阿姆斯特朗编号C ++

1 个答案: