Question

我的代码有问题，每次我用答案'y'循环它（是）它循环到无穷大？

我正在尝试制作一个贷款计算器，每次用户完成交易计算并希望重置，如果他输入值'y'，则进行另一次计算，如果他输入'n'，节目将结束。

到目前为止，这是我的代码：

#include <iostream>
#include <string>
#include <iomanip>
#include <cmath>

using namespace std;
int main() {
    char ans = 'y';

    do {

        string name;
        int Months;
        int n;
        double LoanAmount, Rate, MonthlyInterest, TotalLoanAmount, MonthlyAmortization, OutstandingBalance;
        cout << fixed << showpoint;

        cout << "Enter Name of Borrower: ";
        getline(cin, name);
        cout << "Enter Loan Amount: ";
        cin >> LoanAmount;
        cout << "Enter Number of Months to Pay: ";
        cin >> Months;
        cout << "Enter Interest Rate in Percent(%): ";
        cin >> Rate;

        cout << setprecision(2);
        MonthlyInterest = LoanAmount * Rate;
        TotalLoanAmount = LoanAmount + (MonthlyInterest * Months);

        cout << "Monthly Interest: " << MonthlyInterest << endl
             << "Total Loan Amount with interest: " << TotalLoanAmount << endl;

        cout << setw(100)
             << "\n\tSUMMARY OF OUTSTANDING INSTALLMENT" << endl
             << "\tName of Borrower: " << name
             << "\n\nMonth\t\tMonthly Amortization\t\tOutstanding Balance"
             << "\n";

        for(n = 1; n <= Months; n++) {

            MonthlyAmortization = TotalLoanAmount / Months;
            OutstandingBalance = TotalLoanAmount - MonthlyAmortization;
            cout << n << "\t\t" << MonthlyAmortization << "\t\t\t" << n - 1 << OutstandingBalance << endl;
        }

        cout << "\nEnd of Transaction";
        cout << "Do you want to compute another transaction?[y/n]?" << endl;
        cin >> ans;
    }
    while(ans == 'y');


}

Answer 1

在你的cin＆gt;＆gt; ans之后，添加以下两行：

cin.clear();
cin.sync();

这通常解决了我用cin获得的许多无限循环问题。

另外，我建议不要将ans初始化为＆＃39; y＆＃39;当你宣布它。我不认为这会给你带来麻烦，但这不是一件麻烦事。

Answer 2

您似乎期望按y并输入以仅注册为'y'。如果您只想获得一个字符的输入，请查看std::cin.get(char)

如何获取用户输入以退出循环？

2 个答案: