Question

我正在做另一项家庭作业，我遇到了这个问题。我的2D int [] [] graph1（数组）“无法解析为变量”？

基本上，我将一些图表转换为2D数组，必须将其上传到程序中，如果它们是PATH或CIRCUIT则会读取。一个是有向图，另一个（我现在在其中）是无向的。

这是我到目前为止所做的：

boolean undirectedCircuit (int [][] graph)
{
    //graph = graph1(graph1(null));

    int edgeCounter = 0;

    for (int edge = 0; edge < graph.length; edge++)
    {
        /* SET FOR WHEN 1s are found in array: edgeCounter++;*/
        if(graph[4][4] == '1')
        {
            edgeCounter++;
            System.out.println("edgeCounter found '1' " + edgeCounter + "times");
        }
    }

    if (edgeCounter % 2 == 0)
    {
        System.out.println("This is a circuit!");
        //return true;
    }
    else System.out.println("This is not a circuit!!");
    return false;
    }

public void go ()
{
    graph1 = new int[][] //This line is complained about.
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

    undirectedCircuit(graph1); //This is complained about.
}

任何建议都会很棒！

Answer 1

graph1（array）“无法解析为变量

您尚未声明graph1，因此编译器无法解析符号graph1。

解决方案： -

graph1 = new int[][] //This line is complained about.
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

应该是

int[][] graph1 = 
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

Answer 2

您从未声明graph1。

您应该将graph1 = new int[][] ...更改为int[][] graph1 = new int[][] ...

2D数组无法解析为变量

2 个答案: