Question

基本上，我已经创建了一个自定义Assert方法，该方法声明抛出了异常。这对于我正在进行的某些单元测试来说非常方便

除了将Action作为参数（显然），但不会将属性赋值作为操作。

如何在匿名函数中包装属性赋值？

public static class AssertException
{
    public static void DoesntThrow<T>(Action func) where T : Exception
    {
        try
        {
            func.Invoke();
        }
        catch (Exception e)
        {
            Assert.Fail("No exception was expected but exception of type " 
                + e.GetType() + " with message " + e.Message + " was thrown");
        }
    }

    public static void Throws<T>(Action func, string expectedMessage = "") where T : Exception
    {
        bool exceptionThrown = false;
        try
        {
            func.Invoke();
        }
        catch ( Exception e )
        {
            Assert.IsTrue(e.GetType() == typeof(T), "Expected exception of type " + typeof(T) 
                + " but type of " + e.GetType() + " was thrown instead");
            if (!expectedMessage.Equals(""))
            {
                Assert.AreEqual(e.Message == expectedMessage, "Expected exception with message of "
                    + expectedMessage + " but exception with message " + e.Message + " was thrown instead");
            }
            return;
        }
        Assert.Fail("Expected exception of type " + typeof(T) + " but no exception was thrown");
    }
}

电话：

AssertException.DoesntThrow<Exception>(robot.Instructions = "RLRLMLR");

这给了我：

Error   2   The best overloaded method match for 'RobotWarsTests.AssertException.DoesntThrow<System.Exception>(System.Action)' has some invalid arguments   C:\Users\User\Documents\Visual Studio 2012\Projects\RobotWars\RobotWarsTests\UnitTest1.cs   20  13  RobotWarsTests

Answer 1

AssertException.DoesntThrow<Exception>(() => { robot.Instructions = "RLRLMLR"; });

这将创建一个不带参数()的lambda表达式，并在大括号内执行代码。

如何在匿名方法中包装属性赋值？

1 个答案: