Question

我正在尝试创建一个程序，该程序将接受用户输入，该输入将是一串数字并打印出每个数字出现的次数。但是，我收到一个TypeError，声明int对象不可迭代？我该如何解决这个问题，为什么会发生这种情况？谢谢。

def main():
count = {}
user_input = input("Enter numbers separated by spaces: ")
for number in user_input.split():
    if number in count:
        count[number] = count[number] + 1
    else:
        count[number] = 1
print(count)

for k,v in count.values():
    if v == 1:
        print(k,"occurs one time")
    else:
        print(k,"occurs",v,"times")
main()

Answer 1

对于每个键，检查其值如下：

for key in count:
    if count[key] == 1:
        print(key,"occurs one time")
    else:
        print(key,"occurs",count[key],"times")

count.values()方法仅返回values中的dictionary而不是keys。 count.items()会返回key value对。

Answer 2

替换：

for k,v in count.values():

使用：

for k,v in count.items():

对于您的循环，您需要密钥k和值v。 count.values()将仅返回值。相比之下，count.items()将返回两者。

int对象不可迭代？

2 个答案: