我有这个查询的输出:
select Date,Status, count(distinct persons)from TableA where Date='2014-11-04' group by Status;
+------------+------------------------+-------------------------------+
| Date | Status | count(distinct persons) |
+------------+------------------------+-------------------------------+
| 2014-11-04 | 0 | 45 |
| 2014-11-04 | 1 | 93 |
+------------+------------------------+-------------------------------+
我想得到的是:
+------------+------------------------+-------------------------------+
| Date | 0 | 1 |
+------------+------------------------+-------------------------------+
| 2014-11-04 | 45 | 93 |
+------------+------------------------+-------------------------------+
答案 0 :(得分:3)
您可以使用COUNT
:
CASE
函数中添加条件
SELECT Date,
COUNT(DISTINCT CASE WHEN status = 0 THEN persons END) AS `0`,
COUNT(DISTINCT CASE WHEN status = 1 THEN persons END) AS `1`
FROM TableA
WHERE Date = '2014-11-04'
GROUP BY Date;
答案 1 :(得分:-1)
您可以使用以下代码 -
select Date, [0], [1]
from
(select Date,Status,persons
from TableA
where Date='2014-11-04') AS SourceTable
PIVOT
(
COUNT(persons)
FOR Status IN ([0],[1])
) AS PivotTable;