Question

我有这个代码从XML中获取食物和食物首先，我已将每个restuarnt的名称存储在字符串列表中我想选择列表中的这家餐馆的食物

 foreach(var restaurant in restaurants)
        {
            List<foodplace> foodPlaces = (from _foodplaces in xmlDocument.Element("foodplaces").Elements("foodplace")
                                          where _foodplaces.Value == restaurant 
                                          select new foodplace
                                          {
                                              day = (from day in _foodplaces.Elements(thisDay)
                                                     let list = day.Elements("food").Take(3).ToList()
                                                     select new DayOfWeek
                                                     {
                                                         food1 = (list.Count > 0 ? list[0].Value : string.Empty),
                                                         food2 = (list.Count > 1 ? list[1].Value : string.Empty),
                                                         food3 = (list.Count > 2 ? list[2].Value : string.Empty)
                                                     }).FirstOrDefault()
                                          }).ToList();

问题是_foodplaces从xmldoxument返回看起来像这个

的值

   \n\n\n\t the litle inddian \t\n\n\n

和restuarant值是一个字符串看起来像这个“litle indian”

所以linq语句返回null因为_foodplace不是restuarant 如何来到这个

Answer 1

删除空格并考虑区分大小写：

where String.Equals(_foodplaces.Value.Trim(), restaurant, StringComparison.OrdinalIgnoreCase)

Answer 2

string nameToSearch = "Restaurant12";
string xml = File.ReadAllText(<<pathtoxml>>, Encoding.Default);

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
//this depends on your xml structure: i assumed that the attribute of the restaurant is name
XmlNode node = doc.selectSingleNode("foodplaces/foodplace[@name = '"+nameToSearch +"']");
if(node != null){
    foreach(XmlNode foodNode in node.selectNodes("food")){
        //Do something with the foodnode
        //e.g. foodNode.SelectsingleNode("Price").InnerText
    }
}

Answer 3

在加载xml之前，只需将PreserveWhitespace的{{1}}属性设置为XMLDocument。

false

从xml中选择元素

3 个答案: