Question

SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count
    FROM jobs 
    LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id ='.$id.'' AND jobs.title=''.$title.' group by jobs.id

此查询提供错误：

语法错误，意外'='，期待'，'或';'

Answer 1

问题在于PHP，而不是SQL。

你搞砸了单引号。

更新了查询：

$sql = "SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count
        FROM jobs 
        LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id ='$id' AND jobs.title='$title' group by jobs.id";

Answer 2

试试这个

$your_query = "SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count FROM jobs 
    LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id =".$id." AND jobs.title='".$title."' group by jobs.id";

Answer 3

注意你的报价。这是您的查询修复而不使用双引号：

$query = 'SELECT 
    jobs.id,
    jobs.title, 
    jobs.budget, 
    jobs.views_count, 
    jobs.is_active, 
    count(job_applications.id) as count
    FROM jobs 
LEFT JOIN job_applications ON job_applications.job_id = jobs.id 
WHERE 
    jobs.user_id ='.$id.' 
    AND jobs.title='.$title.' 
group by jobs.id';

如果$title与字符串有关，请使用以下内容，如@daiscog所指出的那样：

$query = 'SELECT 
    jobs.id,
    jobs.title, 
    jobs.budget, 
    jobs.views_count, 
    jobs.is_active, 
    count(job_applications.id) as count
    FROM jobs 
LEFT JOIN job_applications ON job_applications.job_id = jobs.id 
WHERE 
    jobs.user_id ='.$id.' 
    AND jobs.title=\''.$title.'\' 
group by jobs.id';

Answer 4

更改此

jobs.user_id ='.$id.'' AND jobs.title=''.$title.'

到

jobs.user_id ='.$id.' AND jobs.title='.$title.'

在sql中执行以下查询有什么问题

4 个答案: