Question

我需要将带有一些参数的url作为查询字符串，例如：

site.com/controller/action/param1/param2?param3=value&param4=value

有人可以帮我解决这个问题吗？

Answer 1

您应该在config中设置此规则：

'rules'=>array(
    array('controller/action', 'pattern'=>'controller/action/<param1:\w+>/<param2:\w+>'),
)

并创建相同的网址：

Yii::app()->createAbsoluteUrl(
    'controller/action', 
    array('param1'=>'param1value', 'param2'=>'param2value', 'param3'=>'param3value', 'param4'=>'param4value'
);

你得到这个网址：

http://example.com/controller/action/param1value/param2value?param3=param3value&param4=param4value

并获取参数

$_GET['param1'] //'param1value'
$_GET['param2'] //'param2value'
$_GET['param3'] //'param3value'
$_GET['param4'] //'param4value'

Answer 2

我找到了解决方案。我创建了从CBaseUrlRule扩展的组件。

class CCustomUrlRule extends CBaseUrlRule {

private $url;

public function init()
{
    if ($this->name === null) {
        $this->name = __CLASS__;
    }
}
    public function createUrl($manager,$route,$params,$ampersand)
    {
        if ($route === 'controller/index') {
            $this->url = 'controller/';

        if (isset($params['param1'])) {
            $this->url .= 'param1/' . $params['param1'] .'/';
        }

        if (isset($params['param2'])) {
            $this->url .= 'param2/' . $params['param2'] .'/';
        }

        $this->url = substr($this->url, 0, -1);

        if (isset($params['param3']) || isset($params['param4'])) {
            $this->url .= '?';

            if (isset($params['param3']) && isset($params['param4'])) {
                $this->url .= 'param3=' . $params['param3'] .'&';
                $this->url .= 'param4=' . $params['param4'];
            }
            elseif (isset($params['param3'])) {
                $this->url .= 'param3=' . $params['param3'];
            }
            else {
                $this->url .= 'param4=' . $params['param4'];
            }
        }
        return $this->url;
    }
    return false;
}    

    public function parseUrl($manager,$request,$pathInfo,$rawPathInfo)
    {
        return false;
    }
}

我知道 - 这是为了匹配代码，但它很容易定制。

Yii UrlManager部分呈现URL

2 个答案: