寻找下一个回文日期

Question

所以，我正在尝试编写一个程序，它以“mmddyyyy”格式作为输入并返回下一个回文日期（实际上它返回年份，可以反转并预先附加到自身）。以下是我的代码：它给出了正确的结果“我所知道的远近”。现在，我觉得代码既错误又有逻辑漏洞。忽略了我严格遵守“mmddyyyy”输入格式（以及一些硬编码）这​​一事实，您认为代码缺失了什么？

public class NextPalindromeYear {
  // Date in mmddyyyy format
  //12032014
  public int nextPalindromeYear(String date) {
    char[] dateArr = date.toCharArray();
    int[] dateIntArr = new int[dateArr.length];
    int[] numberOfDays = {31,28,31,30,31,30,31,31,30,31,30,31};
    for(int i=0; i < dateArr.length;i++) {
      dateIntArr[i] = dateArr[i] - '0';
    }
    int month = dateIntArr[0] * 10 + dateIntArr[1];
    int day = dateIntArr[2] * 10 + dateIntArr[3];
    int year = 0;int pow = 1;
    for(int i= 7; i > 3; i--) {
      year += dateIntArr[i] * pow ;
      pow *= 10;
    }
    int givenYear = year;
    System.out.println("Month is " + month);
    System.out.println("Date is " + day);
    while(true) {
      System.out.println("Year is " + year);
      int split1 = year / 100;
      int split2 = year % 100;
      split1 = ((split1 % 10) * 10 ) + (split1/10);
      split2 = ((split2 % 10) * 10 ) + (split2/10);

      System.out.println("Split 1 is " + split1);
      System.out.println("Split 2 is " + split2);
      if(split1 >31 || split2 > 11) {
        year++;
        continue;
      }
      if(year%4 == 0) {
        numberOfDays[1] = 29;
      }
      else {
        numberOfDays[1] = 28;
      }
      if(numberOfDays[split2] >= split1) {
        if(year == givenYear) {
          if(!(split1 >= day && split2 > month)) {
            year++;
            continue;
          }
        }
        return year; 
      }
      year++;
    }
  }
}