让synchonousRemote显示来自服务器的自定义错误消息

Question

由于 jQuery validate 中提供的默认远程方法是异步的，因此可以绕过此验证。

来自the answer in this question 修改后的方法可以使远程方法同步。 （Glazed）

//Created for jQuery Validation 1.11.1
$.validator.addMethod("synchronousRemote", function (value, element, param) {
    if (this.optional(element)) {
        return "dependency-mismatch";
    }

    var previous = this.previousValue(element);
    if (!this.settings.messages[element.name]) {
        this.settings.messages[element.name] = {};
    }
    previous.originalMessage = this.settings.messages[element.name].remote;
    this.settings.messages[element.name].remote = previous.message;

    param = typeof param === "string" && { url: param } || param;

    if (previous.old === value) {
        return previous.valid;
    }

    previous.old = value;
    var validator = this;
    this.startRequest(element);
    var data = {};
    data[element.name] = value;
    var valid = "pending";
    $.ajax($.extend(true, {
        url: param,
        async: false,
        mode: "abort",
        port: "validate" + element.name,
        dataType: "json",
        data: data,
        success: function (response) {
            validator.settings.messages[element.name].remote = previous.originalMessage;
            valid = response === true || response === "true";
            if (valid) {
                var submitted = validator.formSubmitted;
                validator.prepareElement(element);
                validator.formSubmitted = submitted;
                validator.successList.push(element);
                delete validator.invalid[element.name];
                validator.showErrors();
            } else {
                var errors = {};
                var message = response || validator.defaultMessage(element, "remote");
                errors[element.name] = previous.message = $.isFunction(message) ? message(value)     : message;
                validator.invalid[element.name] = true;
                validator.showErrors(errors);
            }
            previous.valid = valid;
            validator.stopRequest(element, valid);
        }
    }, param));
    return valid;
}, "Please fix this field.");

但问题是：
默认的远程方法可以显示来自服务器的自定义错误消息，
但 synchronousRemote 方法只能显示来自客户端javascript的默认错误消息或自定义错误消息。

我需要根据值显示不同的错误消息 任何人都知道如何修复 synchronousRemote 方法以显示来自服务器的错误消息？

---

我尝试了一些解决方法。似乎以下代码片段失败因为jQuery.validate只触发一个远程方法。

$(selector).rules('add',{
    synchronousRemote1: '/validation/rule1'
    , synchronousRemote2: '/validation/rule2'
    , messages: {
        synchronousRemote1: 'error msg 1'
        , synchronousRemote2: 'error msg 2'
    }
});

---

当前的工作解决方法使用克隆。

<input type="text" name="clone1" id="clone1" >
<input type="text" name="clone2" id="clone2" style="visibility: hidden; width: 0;" >

和

$('#clone1').rules('add',{
    required: true
    , synchronousRemote: '/validation/rule1'
    , messages: {
        required: ''
        , synchronousRemote: 'errmsg1'
    }
});

$('#clone1').on('keyup',function(){
    $('#clone2').val( $('#clone1').val() ); //copy the value
}).on('blur',function(){
    validator.element('#clone2'); //force validation
});

$('#clone2').rules('add',{
    required: true
    , synchronousRemote: '/validation/rule2'
    , messages: {
        required: ''
        , synchronousRemote: 'errmsg2'
    }
});

这种解决方法似乎有效，但很难看 所以任何人都知道如何正确修复 synchronousRemote 方法以显示来自服务器的错误消息？