使用istream进行反序列化时出现问题>>

时间:2014-12-06 23:47:40

标签: c++ serialization iostream

我正在尝试创建一个名为Serializable的基类,以形式化一些(反)序列化。但是我为下面的代码得到了非常神秘的错误(在http://goo.gl/v92vmb现场运行)。我用gd = c ++ 11和clang ++尝试了g ++ - 4.9,但没有取得更多成功。

有谁可以告诉我什么是错的,也许可以改善这种情况?

#include <iostream>
#include <sstream>

/** Classes inheriting this class must implement the serialize-function...*/
class Serializable {
  public:
    virtual void serialize(std::ostream& os) const = 0;
    virtual void deserialize(std::istream& is) const = 0;
};

std::ostream& operator<< (std::ostream& os, const Serializable& s) {
    s.serialize(os);
    return os;
}

std::istream& operator>> (std::istream& is, const Serializable& s) {
    s.deserialize(is);
    return is;
}

class Foo : public Serializable {
  public:
    int N;
    void serialize(std::ostream& os) const override;
    void deserialize(std::istream& is) const override;
};

void Foo::serialize(std::ostream& os) const {
    os << N;
}
void Foo::deserialize(std::istream& is) const {
    is >> N;
    std::cout << "Got " << N << std::endl;
}

int main()
{
    std::stringstream ss;
    ss << "9";
    Foo f;
    f.deserialize(ss);
    return 0;
}

错误:

In member function 'virtual void Foo::deserialize(std::istream&) 
const':                                                                    
main.cpp:32:11: error: cannot bind 'std::istream {aka std::basic_istream<ch
ar>}' lvalue to 'std::basic_istream<char>&&'                               
     is >> N;                                                              
           ^                                                               
In file included from /usr/include/c++/4.8.3/iostream:40:0,                
                 from main.cpp:1:                                          
/usr/include/c++/4.8.3/istream:872:5: error:   initializing argument 1 of '
std::basic_istream<_CharT, _Traits>& std::operator>>(std::basic_istream<_Ch
arT, _Traits>&&, _Tp&) [with _CharT = char; _Traits = std::char_traits<char
>; _Tp = const int]'                                                       
     operator>>(basic_istream<_CharT, _Traits>&& __is, _Tp& __x) 

1 个答案:

答案 0 :(得分:2)

好的,正如@lisyarus所见,deserialize方法被声明为const。删除它解决了问题。如果只有错误消息更清楚。

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