Question

我刚刚输入了这个小问题，当我完成＃34;学生No.1＆＃34;的细节时，当它到第二个时，它会跳过这个名字。有帮助吗？到目前为止，这是我的代码：

#include<stdlib.h>
#include<iostream>
#include <string>
using namespace std;

int main(){

    int age[3];
    double gpa[3];
    string name[3], level[3];

    cout<<"< < < < < Enter 3 Student Data > > > > >"<<endl;
    for (int x=0; x<3; x++){
    cout<<"-------------------------------"<<endl;
    cout<<"Student No."<<x+1<<endl;
    cout<<"Enter name: ";
    getline(cin, name[x]);
    cout<<"Enter your age: ";
    cin>>age[x];
    cout<<"Enter your GPA: ";
    cin>> gpa[x];
    do{
    cout<<"Enter you grade level [freshman, sophomore, junior, or senior]: ";
    cin>>level[x];
    }while(level[x] != "freshman" && level[x] != "sophomore" && level[x] != "junior" && level[x] != "senior");
    cout<<"-------------------------------"<<endl;
    }

    system("pause");
    cout<<endl<<endl<<"< < < < < Enter 3 Student Datas > > > > >"<<endl;
    for (int x=0; x<3; x++){
    cout<<"-------------------------------"<<endl;
    cout<<"Name: "<<name[x]<<endl<<"Age: "<<age[x]<<endl<<"GPA: "<<gpa[x]<<endl<<"Level: "<<level[x];
    cout<<endl<<"-------------------------------"<<endl;
    //system ("pause");
    }
    return 0;

}

Answer 1

如果你混合使用cin和getline，你必须记住cin通常在键盘缓冲区中留下\ n字符。当getline检查缓冲区时，它会将\ n字符视为第一个并立即结束。在getline函数之前使用cin.ignore删除\ n字符。

在C ++中使用getLine（）时出错

1 个答案: