Question

我在尝试加载表单时遇到了请求上下文错误。

在models.py
在我的视图中创建了def添加
将网址链接到视图

views.py

def add_company(request):
# Get the context from the request.
context = RequestContext(request)

# A HTTP POST?
if request.method == 'POST':
    form = CompanyForm(request.POST)

    # Have we been provided with a valid form?
    if form.is_valid():
        # Save the new category to the database.
        form.save(commit=True)

        # Now call the index() view.
        # The user will be shown the homepage.
        return index(request)
    else:
        # The supplied form contained errors - just print them to the terminal.
        print form.errors
else:
    # If the request was not a POST, display the form to enter details.
    form = CompanyForm()

# Bad form (or form details), no form supplied...
# Render the form with error messages (if any).
return render_to_response('add_company.html', {'form': form}, context)

但是它被困在视图的第一行。我和rango教程一样。它有效。但是我的工作不起作用。有人提示吗？

感谢

请求标题：

Accept  text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Encoding gzip, deflate
Accept-Language de,en-US;q=0.7,en;q=0.3
Cache-Control   max-age=0
Connection  keep-alive
Cookie  csrftoken=I9120vmRATOck4a0SSqlfJPLl62PMUOR; sessionid=isx0p4ezb2y9m129v6243ui3ucuyvrak
Host    localhost:8000
User-Agent  Mozilla/5.0 (X11; Ubuntu; Linux i686; rv:33.0) Gecko/20100101 Firefox/33.0

响应：

Content-Type    text/html
Date    Sun, 07 Dec 2014 22:01:03 GMT
Server  WSGIServer/0.1 Python/2.7.6
X-Frame-Options SAMEORIGIN

Request Method:     GET
Request URL:    http://127.0.0.1:8000/comp/new  
Django Version:     1.7.1
Exception Type:     NameError
Exception Value:    

name 'models' is not defined

Exception Location:     /home/mandaro/django/comp/company/forms.py in CompanyForm, line 5
Python Executable:  /usr/bin/python
Python Version:     2.7.6

GOT it：

Problem wasn t on form - it was template import problem. Imported render_to_response instead of render solved it. Now it can goes on. ciao and tx

Answer 1

您是否忘记导入RequestContext？

from django.template import RequestContext

Answer 2

你实际上不需要担心传递RequestContext，因为如果你使用render()，它会为你处理它。

所以你会这样做：

return render(request, 'add_company.html', {'form': form})

而不是

return render_to_response('add_company.html', {'form': form}, context)

就是这样。当然，你也需要导入它。

from django.shortcuts import render

希望，这可以解决您的问题

Django＆＃39; RequestContext＆＃39;未定义 - forms.ModelForm

2 个答案: