xpath为下面的代码？

Question

我正在尝试为级别等于<fldChar fldCharType="end"/>级别的所有<instrText xml:space="preserve">标记找到xpath。 我尝试了/word/r/instrText/preceding::fldChar但它提供了前面的所有<fldChar fldCharType="end"/>标记。我只需要相同的<fldChar。请建议我解决它。

 <?xml version="1.0" encoding="UTF-8"?>
    <word>
        <r rsidRPr="00A35D44">
                                <rPr>
                                      <rFonts ascii="Times New Roman" eastAsia="Times New Roman"/>
                                    </rPr>
                                <fldChar fldCharType="begin"/>
                              </r>
                          <r rsidRPr="00A35D44">
                                <rPr>
                                      <rFonts ascii="Times New Roman" eastAsia="Times New Roman"/>
                                    </rPr>
                                <instrText xml:space="preserve"> XE “efficiency” </instrText>
                              </r>
                          <r rsidRPr="00A35D44">
                                <rPr>
                                      <rFonts ascii="Times New Roman" eastAsia="Times New Roman"/>
                                    </rPr>
                                <fldChar fldCharType="end"/>
                          </r>
      <fldChar fldCharType="end"/>
                          <r rsidRPr="00A35D44">
                                <rPr>
                                      <rFonts ascii="Times New Roman" eastAsia="Times New Roman"/>
                                      <b val="0"/>
                                    </rPr>
                                <t>,</t>
                              </r>
                          <r rsidRPr="00A35D44">
                                <rPr>
                                      <rFonts eastAsia="Times New Roman" hAnsi="Arial Unicode MS"/>
                                    </rPr>
                                <instrText xml:space="preserve"> and equity</instrText>
                              </r>
                          </word>

Answer 1

根据我们在评论中的交换，您正在寻找表达式//fldChar[@fldCharType="end"][some $it in //instrText[@xml:space = "preserve"] satisfies count(./ancestor::node()) eq count($it/ancestor::node())]。或者更短//fldChar[@fldCharType="end"][some $it in //instrText[@xml:space = "preserve"] satisfies count(ancestor::node()) eq count($it/ancestor::node())]。