Question

由于某种原因，这个AJAX程序不接受我的json对象。

我有一个由registerdb访问的mdf文件，我确信它是正确的。

它有3列：ids，用户名和密码填充数据。

任何帮助都将不胜感激。

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
    $(document).ready(function () {
        $("#<%= btn.ClientID %>").click(function () {
            var User = $("#<%= txtuser.ClientID %>").val();
            var Pass = $("#<%= txtpass.ClientID %>").val();
            var data = "{ Username: " + User + ", Password: " + Pass + " }"
            var json1 = JSON.stringify(data);
            $.ajax({
                type: "POST",
                contentType: "application/json; charset=utf-8",
                url: "Default.aspx/Login",
                data: json1,
                dataType: "json",
                success: function (result) {
                    $("#<%= txtid.ClientID %>").val(result.d);
                },
                error: function (Msg) {
                    $("#<%= lblError.ClientID %>").text('failed:' + Msg.status + ':' + Msg.responseText);

                }
            }); return false;
        }); 
    });
</script>

Default.aspx.cs

[System.Web.Services.WebMethod]
public static string Login(string Username,string Password) 
{
    string ids="";
    string connStr = ConfigurationManager.ConnectionStrings["registerdb"].ConnectionString;
    string cmdStr = "SELECT [ids] FROM [register] WHERE [username]=@username AND [password]=@password;";
    try
    {
        using (SqlConnection conn = new SqlConnection(connStr))
        {
            using (SqlCommand cmd = new SqlCommand(cmdStr, conn))
            {
                conn.Open();
                cmd.Parameters.AddWithValue("@username", Username);
                cmd.Parameters.AddWithValue("@password", Password);
                using (SqlDataReader rdr = cmd.ExecuteReader())
                {
                    if (rdr.Read())
                    {
                        ids = rdr[0].ToString();
                    }
                }
                if (ids == "") { ids = "No Match"; };
                conn.Close();
                cmd.Dispose();
                conn.Dispose();
            }
        }
    }
    catch (Exception ex)
    {
        Console.WriteLine(ex.ToString());
    } 
    return ids;  
}

错误代码：

失败：500：{“消息”：“无法将类型为\ u0027System.String \ u0027的对象转换为类型\ u0027System.Collections.Generic.IDictionary`2 [System.String，System.Object] \ u0027”，“在System.Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeMain的System.Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeInternal（Object o，Type type，JavaScriptSerializer serializer，Boolean throwOnError，Object \ u0026 convertedObject）\ r \ n的StackTrace“：” （Object o，Type type，JavaScriptSerializer serializer，Boolean throwOnError，Object \ u0026 convertedObject）\ r \ n在System.Web.Script.Serialization.JavaScriptSerializer.Deserialize（JavaScriptSerializer serializer，String input，Type type，Int32 depthLimit）\ r \在系统上的System.Web.Script.Serialization.JavaScriptSerializer.Deserialize [T]（字符串输入）\ r \ n处于System.Web.Script.Services.RestHandler.GetRawParamsFromPostRequest（HttpContext上下文，JavaScriptSerializer序列化程序）\ r \ n。 Web.Script.Services.RestHandler.GetRawParams（WebServiceMethodDa ta methodData，HttpContext context）\ r \ n在System.Web.Script.Services.RestHandler.ExecuteWebServiceCall（HttpContext context，WebServiceMethodData methodData）“，”ExceptionType“：”System.InvalidOperationException“}

Answer 1

您的问题是您传入JSON.stringify的数据是字符串，而不是JSON对象。这就是你应该这样做的方式：

var data = {Username:User, Password:Pass};
var json1 = JSON.stringify(data);

后端不接受我的JSON对象

1 个答案: