从lambda表达式获取路径

时间:2014-12-10 07:37:50

标签: c# linq lambda

我有这样的代码:

string PropertyName<T>(Expression<Func<T>> expression)
{
    var body = expression.Body as MemberExpression;

    if (body == null)
    {
        body = ((UnaryExpression)expression.Body).Operand as MemberExpression;
    }

    return body.Member.Name;
}

我以这种方式使用它:

Console.WriteLine(PropertyName(() => this.Property));

在屏幕上打印Property

现在我想改变它:

Console.WriteLine(PropertyName(() => this.OtherObject.Property));

会给我OtherObject.Property而不只是Property。这甚至可能吗?

目的是从代码创建对依赖项属性的绑定,而无需对属性名称进行硬编码。

我还有一个问题body5行等于null的时间是什么时候?我无意识地复制了这段代码并将其留在原处,但这种情况似乎永远不会成真。

1 个答案:

答案 0 :(得分:1)

    string PropertyName<T>(Expression<Func<T>> expression)
    {
        var body = expression.Body as MemberExpression;

        if (body == null)
        {
            body = ((UnaryExpression)expression.Body).Operand as MemberExpression;
        }

        return string.Join(".", GetPropertyNames(body).Reverse());
    }

    private IEnumerable<string> GetPropertyNames(MemberExpression body)
    {
        while (body != null)
        {
            yield return body.Member.Name;
            var inner = body.Expression;
            switch (inner.NodeType)
            {
                case ExpressionType.MemberAccess:
                    body = inner as MemberExpression;
                    break;
                default:
                    body = null;
                    break;

            }
        }
    }