如何从子fxml组件的动作执行中更改父fxml内容?

时间:2014-12-10 17:45:27

标签: javafx fxml

我创建了JavaFX应用程序,并希望在具有层次结构和MVC结构的不同FXML之间分发完整的功能。

在开始时RoolLayout.fxml是父FXML的加载

RootLayout.fxml

<BorderPane prefHeight="400.0" prefWidth="1000.0" xmlns="http://javafx.com/javafx/8" xmlns:fx="http://javafx.com/fxml/1" fx:controller="com.nikunj.drclinic.controller.RootLayoutController">
<center>
  <AnchorPane fx:id="dashboard" BorderPane.alignment="CENTER" />
</center>
<top>
  <HBox BorderPane.alignment="CENTER">
     <children>
        <fx:include fx:id="mainMenu" source="MainMenuBar.fxml" />
     </children>
  </HBox>
</top>
</BorderPane>

对于这个使用过的控制器是RootLayoutController.java

public class RootLayoutController {

 @FXML
 private MainMenuBarController mainMenuBarController;

 @FXML
 private AnchorPane dashboard;

 @FXML
 private void initialize() {
    // Initialize the person table with the two columns.
 }
}

从内部加载MainMenuBar.fxml文件,这是子fxml文件

MainMenuBar.fxml

<AnchorPane xmlns="http://javafx.com/javafx/8" xmlns:fx="http://javafx.com/fxml/1" fx:controller="com.nikunj.drclinic.controller.MainMenuBarController">
   <children>
      <MenuBar layoutY="2.0" prefWidth="1000.0" AnchorPane.bottomAnchor="0.0" AnchorPane.leftAnchor="0.0" AnchorPane.rightAnchor="0.0" AnchorPane.topAnchor="0.0">
        <menus>
          <Menu mnemonicParsing="false" text="File">
            <items>
              <MenuItem mnemonicParsing="false" onAction="#closeApplication" text="Close" />
            </items>
          </Menu>
          <Menu mnemonicParsing="false" text="Patient Detail">
            <items>
              <MenuItem fx:id="addPatiendMenuItem" mnemonicParsing="false" onAction="#addPatient" text="Add Patient" />
                  <MenuItem mnemonicParsing="false" text="Find Patient" />
            </items>
          </Menu>
        </menus>
      </MenuBar>
   </children>
</AnchorPane>

此MainMenuBar.fxml的控制器文件是MainMenuBarController.java

public class MainMenuBarController {

 @FXML
 private MenuItem addPatiendMenuItem;

 @FXML
 private MenuItem findPatientMenuItem;

 @FXML
 public void closeApplication(){
    System.exit(0);
 }

 @FXML
 public void addPatient(ActionEvent event){

 }
}

现在从控制器选择菜单项addPatiendMenuItem调用addPatient(ActionEvent事件)方法。 从这个方法我怎么能改变AnchorPane fx:id =&#34; dashboard&#34;它是父fxml(RootLayout.fxml)文件的组成部分。

假设我想在此AnchorPane中加载第三个fxml(即Dashboard.fxml)的内容,我该怎么做?

我花了很多时间来查找,如何从子控制器组件上执行的操作中更改父控制器组件?

1 个答案:

答案 0 :(得分:1)

MainMenuBarController中创建一个表示您要更改的状态的属性(&#34;查看状态&#34;)。让它变得有意义取决于对应用程序的了解更多,但你可能会做类似

的事情
public class MainMenuBarController {
    private final BooleanProperty addPatientRequested = new SimpleBooleanProperty();
    public BooleanProperty addPatientRequestedProperty() {
        return addPatientRequested ;
    }
    public final boolean isAddPatientRequested() {
        return addPatientRequestedProperty().get();
    }
    public final boolean setAddPatientReqested(boolean requested) {
        addPatientReqestedProperty().set(requested);
    }

    @FMXL
    private void addPatient(ActionEvent event) {
        setAddPatientRequested(true);
    }
}

然后在&#34;父母&#34;控制器

public class RootLayoutController {

 @FXML
 private MainMenuBarController mainMenuBarController;

 @FXML
 private AnchorPane dashboard;

 @FXML
 private void initialize() {
    // Initialize the person table with the two columns.
    mainMenuBarController.addPatientRequestedProperty().addListener((obs, wasRequested, isNowRequested) -> {
        if (isNowRequested) {
            // code to execute...
        }
    });
 }
}

根据您的应用程序逻辑,您可能需要不同的属性,例如在MainMenuBarController定义

ObjectProperty<Node> display = new SimpleObjectProperty<>();

将存储RootLayoutController应显示的节点。结构类似,在addPatient处理程序方法中设置该属性并在RootLayoutController

中监听它
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