Question

我有这个Party类，它包含来自服务的object数据类型。它可以包含Item属性的两种不同成员类型。

public class Party
{
    public string DMVID {get; set;}
    public object Item { get; set; }
}

和这个DTO

public class PartyDTO
{
    public string DMVID {get; set;}
    public BusinessDTO BusinessItem { get; set; }
    public IndividualDTO IndividualItem { get; set; }
}

如何将Item的输出映射到BusinessItem或IndividualItem。我知道这个不行。 Mapper.CreateMap<Party, PartyDTO>(); 我不知道条件映射是否可以解决这个问题，或者像one这样的解析器。

Answer 1

嘿，也许这会帮助你！我测试了它，但我只使用了AutoMapper两天！

好的，这是你的着名课程!!!

    public class Party
{
    public string DMVID { get; set; }
    public object Item { get; set; }
}


public class PartyDTO
{
    public string DMVID { get; set; }
    public BuisnessDTO BusinessItem { get; set; }
    public IndividualDTO IndividualItem { get; set; }
}


public class BuisnessDTO
{
    public int Number
    {
        get;
        set;
    }
}

public class IndividualDTO
{
    public string Message
    {
        get;
        set;
    }
}

这里是你当前场景的MapperConfiguration！

    // Edit There was no need here for some conditions
  AutoMapper.Mapper.CreateMap<Party, PartyDTO>()
                .ForMember(dto => dto.BusinessItem, map => 
                    map.MapFrom(party => party.Item as BuisnessDTO);
                )
                .ForMember(dto => dto.IndividualItem, map =>
                    map.MapFrom(party => party.Item as IndividualDTO);
                );

    // And this is another way to achive the mapping in this scenario
                AutoMapper.Mapper.CreateMap<PartyDTO, Party>()
                    .ForMember(party => party.Item, map => map.MapFrom( dto => (dto.BusinessItem != null) ? (dto.BusinessItem as object) : (dto.IndividualItem as object)));

我为它创建了这个样本！

            Party firstParty = new Party()
        {
            DMVID = "something",
            Item = new BuisnessDTO()
            {
                Number = 1
            }
        };


        Party secondParty = new Party()
        {
            DMVID = "something",
            Item = new IndividualDTO()
            {
                Message = "message"
            }
        };



        PartyDTO dtoWithBuisness = AutoMapper.Mapper.Map<PartyDTO>(firstParty);
        PartyDTO dtoWithIndividual = AutoMapper.Mapper.Map < PartyDTO>(secondParty);

        Party afterParty = AutoMapper.Mapper.Map<Party>(dtoWithBuisness);
        afterParty = AutoMapper.Mapper.Map < Party>(dtoWithIndividual);

当然还有其他可能性，但我认为这正是你想要的。

Automapper，将一个对象成员类型映射到多个具体类型

1 个答案: