Question

我需要验证需要满足以下规则的密码：

最小长度为8个字符
所有字符都必须是唯一的
至少有一个字符大写
至少有一个字符是非字母字符，数字或连字符
不应将非字母字符作为前两个或最后两个字符放置

我无法弄清楚如何使用正则表达式来验证这一点。有人能帮助我吗？

Answer 1

^(?=.*[A-Z])(?=.*(?:\d|-))(?!.*(.).*\1)[a-zA-Z]{2}.{4,}[a-zA-Z]{2}$

试试这个。看看演示。

https://regex101.com/r/eZ0yP4/12

正如您所看到的那样，在前瞻的帮助下，所有条件都得到了满足。

(?=.*[A-Z]) ===至少有一个资本

(?=.*(?:\d|-)) ===至少一位数或-

(?!.*(.).*\1) ===没有重复

[a-zA-Z]{2}.{4,}[a-zA-Z]{2} ===字母字符为前两个和后两个。

Answer 2

您可以使用vt password library。代码很长，但很容易修改它，并且它非常易于维护。

// password must be between 8 and 16 chars long
LengthRule lengthRule = new LengthRule(8, 16);

// don't allow whitespace
WhitespaceRule whitespaceRule = new WhitespaceRule();

// control allowed characters
CharacterCharacteristicsRule charRule = new CharacterCharacteristicsRule();
// require at least 1 digit in passwords
charRule.getRules().add(new DigitCharacterRule(1));
// require at least 1 non-alphanumeric char
charRule.getRules().add(new NonAlphanumericCharacterRule(1));
// require at least 1 upper case char
charRule.getRules().add(new UppercaseCharacterRule(1));
// require at least 1 lower case char
charRule.getRules().add(new LowercaseCharacterRule(1));
// require at least 3 of the previous rules be met
charRule.setNumberOfCharacteristics(3);
// don't allow alphabetical sequences
AlphabeticalSequenceRule alphaSeqRule = new AlphabeticalSequenceRule();

// don't allow numerical sequences of length 3
NumericalSequenceRule numSeqRule = new NumericalSequenceRule(3);

// don't allow qwerty sequences
QwertySequenceRule qwertySeqRule = new QwertySequenceRule();

// don't allow 4 repeat characters
RepeatCharacterRegexRule repeatRule = new RepeatCharacterRegexRule(4);

// group all rules together in a List
List<Rule> ruleList = new ArrayList<Rule>();
ruleList.add(lengthRule);
ruleList.add(whitespaceRule);
ruleList.add(charRule);
ruleList.add(alphaSeqRule);
ruleList.add(numSeqRule);
ruleList.add(qwertySeqRule);
ruleList.add(repeatRule);

PasswordValidator validator = new PasswordValidator(ruleList);
PasswordData passwordData = new PasswordData(new Password("testpassword"));

RuleResult result = validator.validate(passwordData);
if (result.isValid()) {
  System.out.println("Valid password");
} else {
  System.out.println("Invalid password:");
  for (String msg : validator.getMessages(result)) {
    System.out.println(msg);
  }
}

复杂密码的正则表达式

2 个答案: