Question

我要检查用户团队发布的1天后未被排除的挑战，然后自动退还用户的团队，然后删除所有挑战。到目前为止，这是我的代码。

//Delete all matches not accepted after 1 day
$arrayin = array();
$autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " "
        . "AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < " . ((int) time()) . ")");
if (mysql_num_rows($autorefund) > 0) {
    while ($autorefund = mysql_fetch_assoc($autorefund)) {
        $arrayin[] = $autorefund['id'];
        mysql_query("UPDATE `teams` SET `balance` =  `balance` + " . $autorefund['credits'] . " "
                . "WHERE `id` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ")");
        mysql_query("DELETE FROM `challenges` WHERE `a` IN "
                . "(" . mysql_real_escape_string(implode(',', $arrayin)) . ") "
                . "AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 "
                . "AND (`expires` < " . ((int) time()) . ")");
    }
}

Answer 1

你需要发布更新的MySQL，删除循环中的条件。

你已经在循环中获得了ids。

所以，最终的代码应该是：

 //Delete all matches not accepted after 1 day
    $arrayin              = array();
    $autorefund   = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")");
    if (mysql_num_rows($autorefund) > 0) {
        while ($autorefund  = mysql_fetch_assoc($autorefund)) {
             $arrayin[] = $autorefund['id'];
        }
    }
mysql_query("UPDATE `teams` SET `balance` =  `balance` + " . $autorefund['credits'] . " WHERE `id` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ")");
mysql_query("DELETE FROM `challenges` WHERE `a` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ") AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")");

不要使用mysql_函数，因为它们已被弃用，将在未来的PHP版本中删除。

Answer 2

无需移动ID（使用select获取id到客户端代码，然后使用IN子句创建查询），您可以使用正确的SQL一次更新和删除。有点像：

$now = time();

mysql_query("START TRANSACTION");

$sql = "
UPDATE teams t JOIN challenges c
    ON t.id = c.id
   SET t.balance = t.balance + c.credits
 WHERE c.a = %d  
   AND c.accepted = 0 
   AND c.completed = 0 
   AND c.chtype = 1 
   AND c.expires < %d";
$sql = sprintf($sql, $team['id'], $now);
$update = mysql_query($sql);

$sql = "
DELETE 
  FROM challenges   
 WHERE a = %d  
   AND accepted = 0 
   AND completed = 0 
   AND chtype = 1 
   AND expires < %d";
$sql = sprintf($sql, $team['id'], $now);
$delete = mysql_query($sql);

if ($update && $delete) {
    mysql_query("COMMIT");
} else {
    mysql_query("ROLLBACK");
}

Answer 3

$ arrayin = array（）;

$ autorefund = mysql_query（“SELECT * FROM challenges WHERE a =”。$ team ['id']。“” 。 “AND accepted = 0 AND completed = 0 AND chtype = 1 AND（expires＆lt;”。（（int）time（））。“）”）;

if（mysql_num_rows（$ autorefund）＆gt; 0）{

while ($autorefund = mysql_fetch_assoc($autorefund)) {

    $arrayin[] = $autorefund['id'];

    mysql_query("UPDATE `teams` SET `balance` =  `balance` + " . $autorefund['credits']. " WHERE `id`='".$autorefund['id']."'");
 }
     mysql_query("DELETE FROM `challenges` WHERE `id` IN "
            . "(" . mysql_real_escape_string(implode(',', $arrayin)) . ") "
            . "AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 "
            . "AND (`expires` < " . ((int) time()) . ")");

}

Answer 4

$query = "SELECT * FROM challenges
WHERE `a` = {$team['id']} AND accepted = 0 AND completed = 0 AND chtype = 1 AND expires < UNIX_TIMESTAMP()";

$result = mysql_query($query);


if(mysql_num_rows($result) > 0){ 
   $arrayin = array(); 
while($row  = mysql_fetch_assoc($result)){

mysql_query("UPDATE teams SET balance = balance + {$row['credits']} WHERE id = {$row['a']}");
   $arrayin[] = $row['id']; 
}

mysql_query("DELETE FROM challenges WHERE id IN(".implode(',',$arrayin).")");

}

更新＆amp;使用id的数组删除多行

4 个答案: