查询
SELECT AV.ItemID as ItemIDe, AV.uid, ui.Count, U.Name, u.Surname,
u.UID as UserID, av.Value, av1.Value, AV2.Value
FROM AttribValues as AV
full join AttribValues as AV2 on AV2.AttribID = 3 AND AV2.Value = '12'
AND AV2.ItemID = AV.ItemID
full join AttribValues as AV1 on AV1.AttribID = 2 AND AV1.Value = 'zielony'
AND AV1.ItemID = AV.ItemID
join UsersItems as UI on Ui.UID = AV.ItemID
join Users as U on u.UID = ui.UserID
WHERE ((AV.AttribID = 1 AND AV.Value = '517750069') OR (AV1.Value IS NOT NULL
OR AV2.Value IS NOT NULL)) AND DateEnd > GETDATE ()
并且在Av.ItemID
中有重复记录答案 0 :(得分:0)
它会是这样的:
SELECT COUNT(1), AV.ItemID as ItemIDe, AV.uid, ui.Count, U.Name, u.Surname, u.UID as UserID, av.Value, av1.Value, AV2.Value
FROM AttribValues as AV
full join AttribValues as AV2 on AV2.AttribID = 3 AND AV2.Value = '12' AND AV2.ItemID = AV.ItemID
full join AttribValues as AV1 on AV1.AttribID = 2 AND AV1.Value = 'zielony' AND AV1.ItemID = AV.ItemID
join UsersItems as UI on Ui.UID = AV.ItemID
join Users as U on u.UID = ui.UserID
WHERE ((AV.AttribID = 1 AND AV.Value = '517750069') OR (AV1.Value IS NOT NULL OR AV2.Value IS NOT NULL)) AND DateEnd > GETDATE ()
GROUP BY AV.ItemID, AV.uid, ui.Count, U.Name, u.Surname, u.UID, av.Value, av1.Value, AV2.Value
HAVING COUNT(1) > 1