如何检测UIButton按压状态？

Question

我想在按下按钮时连续调用方法。我可以使用内部触摸或其他类似动作来检测UIButton按下状态。那么如何检测UIButton按压状态？

Answer 1

我是这样做的：

UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressRecordButton:)];
[self.view.recordBtn addGestureRecognizer:longPress];
UIButton *recordButton = self.view.recordBtn;
[recordButton addTarget:self action:@selector(beginTouchRecord:) forControlEvents:UIControlEventTouchDown];
[recordButton addTarget:self action:@selector(endTouch:) forControlEvents:UIControlEventTouchUpInside];
[recordButton addTarget:self action:@selector(endTouch:) forControlEvents:UIControlEventTouchCancel];

Answer 2

您只能为此状态获取操作方法

typedef NS_OPTIONS(NSUInteger, UIControlEvents) {
UIControlEventTouchDown           = 1 <<  0,      // on all touch downs
UIControlEventTouchDownRepeat     = 1 <<  1,      // on multiple touchdowns (tap count > 1)
UIControlEventTouchDragInside     = 1 <<  2,
UIControlEventTouchDragOutside    = 1 <<  3,
UIControlEventTouchDragEnter      = 1 <<  4,
UIControlEventTouchDragExit       = 1 <<  5,
UIControlEventTouchUpInside       = 1 <<  6,
UIControlEventTouchUpOutside      = 1 <<  7,
UIControlEventTouchCancel         = 1 <<  8,

UIControlEventValueChanged        = 1 << 12,     // sliders, etc.

UIControlEventEditingDidBegin     = 1 << 16,     // UITextField
UIControlEventEditingChanged      = 1 << 17,
UIControlEventEditingDidEnd       = 1 << 18,
UIControlEventEditingDidEndOnExit = 1 << 19,     // 'return key' ending editing

UIControlEventAllTouchEvents      = 0x00000FFF,  // for touch events
UIControlEventAllEditingEvents    = 0x000F0000,  // for UITextField
UIControlEventApplicationReserved = 0x0F000000,  // range available for application use
UIControlEventSystemReserved      = 0xF0000000,  // range reserved for internal framework use
UIControlEventAllEvents           = 0xFFFFFFFF
};