如何使用executeUpdate()删除具有GORM(Grails)和HQL(Hibernate)的实体

时间:2014-12-17 15:36:06

标签: sql hibernate grails gorm

在我的用例中,我想删除与特定testEntity(从外部作为参数传递)和任何类型LabelTestEntity的标签相关联的SUB_LABEL的所有条目。要做到这一点,我使用grails executeUpdate()方法,在我看来应该是这样的:

LabelTestEntity.executeUpdate("DELETE FROM LabelTestEntity WHERE testEntity= :TEST and label.labelType= :TYP", 
  [TEST: testEntity, TYP: Label.Type.SUB_LABEL])

不幸的是,这会导致SQL语法错误:

Error |
2014-12-17 16:14:06,130 [http-nio-8080-exec-2] ERROR util.JDBCExceptionReporter  - Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]
Error |
2014-12-17 16:14:06,210 [http-nio-8080-exec-2] ERROR errors.GrailsExceptionResolver  - JdbcSQLException occurred when processing request: [POST] /cartoapp/mapping/groupedReassignOfSubLabels
Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]. Stacktrace follows:
org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]
        at org.h2.message.DbException.getJdbcSQLException(DbException.java:344)
        at org.h2.message.DbException.get(DbException.java:178)
        at org.h2.message.DbException.get(DbException.java:154)
        at org.h2.message.DbException.getSyntaxError(DbException.java:190)
        at org.h2.command.Parser.getSyntaxError(Parser.java:517)
        at org.h2.command.Parser.prepareCommand(Parser.java:246)

示例来源:HQLGORM

到目前为止我尝试了什么:

  1. 删除FROM结果:只是语法糖,并且总是在内部使用
  2. 使用别名。 结果:错误相同的行为
  3. 仅使用一个条件尝试相同的查询。

    LabelTestEntity.executeUpdate("DELETE FROM LabelTestEntity WHERE testEntity= :TEST", [TEST: testEntity])

    结果此作品,无论与哪种类型的标签相关联,特定测试的所有LabelTestEntity都会被删除。

  4. 这使我得出结论,使用ANDWHERE块添加第二个条件会导致语法错误。有人可以建议或有人知道 - 这里有什么问题?

    ---- ---- EDIT 以下是域类之间的关系:

    class LabelTestEntity implements Serializable {
      Label label
      TestEntity testEntity
    
      static mapping = {
        id composite: ['label', 'testEntity']
      }
    }
    
    class Label {
    
      //0 FOR MAIN_LABEL 1 FOR SUB_LABEL, 2 FOR TECH_LABEL
      enum Type {
          MAIN_LABEL, SUB_LABEL, TECH_LABEL
          private final int value;
    
          private Type() {
            this.value = ordinal();
          }
      }
    
      String name 
      Application application
      String description
      Type labelType
    
      static constraints = {
        name blank: false
        application blank: false
        description nullable : true
      }
    
      static mapping = {
        labelType enumType:"ordinal"
       }
    }
    

1 个答案:

答案 0 :(得分:0)

因此,经过一番努力,我们发现DELETE不支持联接,但尝试访问相关Label实体的属性会在内部转换为联接。

解决方案是预先选择要删除的LabelTestEntity - 然后删除这些实体。

  LabelTestEntity.executeUpdate("DELETE LabelTestEntity lte "
    + "WHERE lte.id IN ( SELECT lte2.id FROM LabelTestEntity lte2 WHERE lte2.testEntity= :TEST "
    + "AND lte2.label.labelType= :TYP)", [TEST: testEntity, TYP: labelType])

为了使预选更轻量级并且仅通过ID删除,有必要删除“LabelTestEntity”的静态映射,这将改变生成ID的方式。

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