Question

我收到了错误：

/ feeds / upload
上的IntegrityError

我尝试使用＆＃39;外键关键方法连接用户模型和Feed模型。

这是我的model.py：

 class feed(models.Model):
    user = models.ForeignKey(User,null=True,blank=True)
    feed_text = models.CharField(max_length=2000)
    date = models.DateField()
    upvote = 0
    downvote = 0

    def __str__(self):
        return feed.content

class comments(models.Model):
    feed = models.ForeignKey(feed,null=True,blank=True)

    comment_text = models.CharField(max_length=600)
    user = models.ForeignKey(User)

    def __str__(self):
        return comments.comment_text

在form.py中：

from django import forms
from .models import *

class feed_form(forms.ModelForm):
class Meta:
    model = feed
    fields = ('feed_text',  )

在views.py中：

def upload(request):
    feed_cont = feed_form(data=request.POST)
    feed_cont.user = User.objects.get(id =1)
    print(feed_cont.user.id)
    feed_cont.upvote = 0
    feed_cont.downvote =0

    feed_cont.save()

    return  render(request,'feeds/feeds.html')

但是当我试图打印uesr.id时，它起作用..我不知道我在哪里弄错了.. 请帮我解决这个问题.. 提前谢谢..

Answer 1

您应该将属性设置为不是表单，而是设置为模型实例：

form = feed_form(request.POST)
feed_cont = form.save(commit=False)  
feed_cont.user = User.objects.get(id=1)
feed_cont.upvote = 0
feed_cont.downvote = 0
feed_cont.save()

Django：（1048，＆＃34;专栏＆＃39; user_id＆＃39;不能为空＆＃34;）

1 个答案: