Question

如果我运行代码，它将停止并且不执行任何操作，我无法键入。似乎是一个无限循环。问题似乎是循环结束，但如果我把它拿出来，我的条件将无法满足。谁能找到解决方案？我已经尝试了所有我能想到的循环。

/. 2d array board ./

board = Array.new(10) { Array.new(10, 0) }

/. printing board ./

if board.count(5) != 5 && board.count(4) != 4 && board.count(3) != 3

  for i in 0..9
    for j in 0..9
      board[i][j] = 0
    end
  end

  aircraftcoord1 = (rand*10).floor
  aircraftcoord2 = (rand 6).floor
  aircraftalign = rand
  if aircraftalign < 0.5
    for i in 0..4
      board[aircraftcoord2+i][aircraftcoord1] = 5
    end
  else
    for i in 0..4
      board[aircraftcoord1][aircraftcoord2+i] = 5
    end
  end

  cruisercoord1 = (rand*10).floor
  cruisercoord2 = (rand 7).floor
  cruiseralign = rand
  if cruiseralign < 0.5
    for i in 0..3
      board[cruisercoord2+i][cruisercoord1] = 4
    end
  else
    for i in 0..3
      board[cruisercoord1][cruisercoord2+i] = 4
    end
  end

  destroyercoord1 = (rand*10).floor
  destroyercoord2 = (rand 8).floor
  destroyeralign = rand
  if destroyeralign < 0.5
    for i in 0..2
      board[destroyercoord2+i][destroyercoord1] = 3
    end
  else
    for i in 0..2
      board[destroyercoord1][destroyercoord2+i] = 3
    end
  end

end until board.count(5) == 5 && board.count(4) == 4 && board.count(3) == 3


print " "

for i in 0..9
  print i
end

puts

for i in 0..9
  print i
  for j in 0..9
    print board[i][j]
  end
  puts
end

Answer 1

board.count(5) == 5 ...行永远不会成立，因为board是一个二维数组。我不知道条件应该是什么，但它可能看起来像：

  board[5].count(5) == 5

ruby代码在运行时停止，看似无限循环

1 个答案: