观察者未添加

时间:2014-12-25 17:22:50

标签: java

我目前正在研究Java应用程序,它每秒都会检查计算机的温度。为了时间的关系,我创建了一个与Timer一起使用的Quartz类,并且为了检查温度,我创建了一个名为SysKeeper的类。我的问题是,我想要的是,SysKeeper会在Timer被触发时被通知,但我的Observer无效,因为Syskeeper未被添加为Observer

在这里,您可以看到我的Syskeeper课程:

public class SysKeeper implements Observer {
    private double temp;

    public void start() {
        Log.info("SysKeeper starting");
        Main.timer.addObserver(this);
    }

    private void checkTemp() {
        String buffer = CmdExecutor.execute("sudo vcgencmd measure_temp");
        String[] splitBuffer = buffer.split("=");
        String[] splitBuffer1 = splitBuffer[1].split("\'");
        temp = Double.parseDouble(splitBuffer1[0]);
        if (temp > 70.0) {
            //Main.not.sendMessage("Reached crit Temp: " + temp);
        }
        Log.info(temp + "");
    }

    public void kill() {
    }

    @Override
    public void update(Observable o, Object arg) {
        System.out.println("HI");
        this.checkTemp();
    }
}

这是我的Timer课程:

public class Timer extends Observable implements Job {

    public void start() {
        try {
            Trigger trigger = TriggerBuilder
                    .newTrigger()
                    .withIdentity("timer", "timer")
                    .withSchedule(
                            CronScheduleBuilder.cronSchedule("0/1 * * * * ?"))
                    .build();

            JobDetail job = JobBuilder.newJob(Timer.class)
                    .withIdentity("timer", "timer").build();

            Scheduler scheduler = new StdSchedulerFactory().getScheduler();
            scheduler.start();
            scheduler.scheduleJob(job, trigger);
        } catch (SchedulerException ex) {
            Logger.getLogger(Timer.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    @Override
    public void execute(JobExecutionContext jec) throws JobExecutionException {
        this.setChanged();
        this.notifyObservers();
        System.out.println("" + countObservers());//always 0
    }

    public void kill() {

    }
}

这也是我的Main课程:

public class Main {

    public static final String spliterNetwork = ";";
    public static final String spliterParameter = "#";

    public static Timer timer;
    public static Server ser;
    public static SysKeeper kep;
    public static GPIO gpio;
    public static Log log;

    public static void main(String[] args) throws UnknownHostException {
        Main.init(args);
        Main.start();

        Runtime.getRuntime().addShutdownHook(new Thread(new Runnable() {
            @Override
           public void run() {
                Main.stop();
            }
        }));
    }

    public static void init(String[] args) {
       timer = new Timer();
        log = new Log();
        ser = new Server();
        kep = new SysKeeper();
        gpio = new GPIO();
    }

    public static void start() throws UnknownHostException {
        Log.info("Welcome to iServer @ " + InetAddress.getLocalHost());
        timer.start();
        log.start();
        ser.start();
        kep.start();
        gpio.start();
    }

    public static void stop() {
        Log.info("Programm shuts down");
        timer.kill();
        log.kill();
        ser.kill();
        kep.kill();
        gpio.kill();

        timer = null;
        log = null;
        ser = null;
        kep = null;
        gpio = null;
        Log.info("Good bye");
   }
}

1 个答案:

答案 0 :(得分:1)

我对Quartz不熟悉,但似乎你有两个不同的Timer实例:

  • Timer中存储的第一个Main.timer,在timer = new Timer()中创建,并在Main.timer.addObserver(this);SysKeeper中)添加了观察者。永远不会执行此实例,也就是说,它永远不会调用execute()方法。
  • 由行Timer中的第一个Timer创建的第二个JobDetail job = JobBuilder.newJob(Timer.class)...Timer是正在执行的scheduler.scheduleJob(job, trigger);Observer)但它没有任何{{1}}附加。
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