Question

我想获得不同的"SkillCategory"并按id

排序

这是以下脚本：

SELECT  distinct EC.SKILL_CATEGORY from ETOPS_CHECK_FORM E
INNER JOIN EC_FORM_SKILL EC
ON EC.EC_FORM_ID=E.ID group by EC.SKILL_CATEGORY ORDER BY EC.ID

我做错了什么？

Answer 1

问题是您需要决定要排序的 ID。删除distinct，然后在order by：

中使用聚合函数

SELECT EC.SKILL_CATEGORY
FROM ETOPS_CHECK_FORM E INNER JOIN
     EC_FORM_SKILL EC
     ON EC.EC_FORM_ID = E.ID
GROUP BY EC.SKILL_CATEGORY
ORDER BY MIN(EC.ID);

Answer 2

如果您只想要不使用聚合函数的不同记录，请使用 DISTINCT 关键字而不是 GROUP BY

试试这个：

SELECT DISTINCT EC.SKILL_CATEGORY 
FROM ETOPS_CHECK_FORM E
INNER JOIN EC_FORM_SKILL EC ON EC.EC_FORM_ID = E.ID 
ORDER BY EC.ID;

Answer 3

SELECT  distinct EC.SKILL_CATEGORY 
FROM ETOPS_CHECK_FORM E
  INNER JOIN EC_FORM_SKILL EC
          ON EC.EC_FORM_ID=E.ID 
GROUP BY EC.SKILL_CATEGORY ASC
ORDER BY MAX(EC.ID)

Answer 4

我想知道你真正想做什么...... ^^ 但是，如果您运行下面的脚本，您能否告诉我们结果是否符合您的期望：

Select ec.skill_category as sc
from EC_FORM_SKILL ec
group by sc;

稍后见。

ORA-01791-区别和订购

4 个答案: