根据ajax成功回调返回值退出父函数

时间:2014-12-29 06:11:56

标签: php jquery ajax

//this function will upload file through ajax
add: function (e, data) {

        //before upload file check server has that file already uploaded
        $.ajax(
                {
                    type: "POST",
                    dataType:'json',
                    url:"../admin/cgi/file_check.php",
                    async:false,
                    data:{  
                             filename : upload_filename,
                             docname : upload_docname,
                             userid : upload_userid,
                        },
                    success:function(data)
                    {
                        //check file alreay exists
                        if(data['doc_name'] == 'invalid')
                        {
                            // if file alreay exists want to stop upload process
                            //exit from main funtion
                        }

                    },
                    error:function(request,errorType,errorMessage) 
                    {
                        alert ('error - '+errorType+'with message - '+errorMessage);
                    }
            });

            //file uploading code

            }

add: function (e, data) {} - 主要功能通过ajax上传文件 在上传之前,检查服务器已经通过ajax请求上传了该文件 如果文件alreay存在,则ajax成功回调返回值data['doc_name'] = 'invalid'

如果文件alredy存在if(data['doc_name'] == 'invalid')我想停止上传进程(想要退出主上传功能)

1 个答案:

答案 0 :(得分:1)

您可以尝试这样做:如果您的ajax返回无效,则显示错误消息,否则上传文件。

success:function(data)
 {
       //check file alreay exists
       if(data['doc_name'] != 'invalid')
       {
             //file uploading code
       }
       else
       {
            // Display your error message.
       }
 },
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