在django rest框架中序列化相关对象

时间:2014-12-29 11:59:30

标签: django rest python-2.7 django-rest-framework django-serializer

如何在DRF中序列化相关对象。我有三个模型auth_user(User),ModelA,ModelB。

我的模特:

class ModelA(models.Model):
  user = models.OneToOneField(auth_user, related_name = 'modelA')
  name = models.CharField(max_length = 30)

class ModelB(models.Model):
  owner = models.OneToOneField(auth_user)
  user = models.OneToOneField(auth_user, related_name = 'modelB')
  type = models.ForeignKey(ModelD)
  cost = models.IntegerField()

class ModelD(models.Model):
  type_desc = models.CharField(max_length = 40)

我的序列化器:

class A(serializers.ModelSerializer):

   class Meta:
    model = ModelA
    fields = ('name', )

class B(serializers.ModelSerializer):

  class Meta:
     model = ModelB
     fields = ('type', 'cost', )

class AuthUserSerilaizer(serializers.ModelSerializer):

  userA = serializers.RelatedField(source = 'modelA')
  userB = serializers.RelatedField(source = 'modelB')

  class Meta:
    model = User
    fields = ('email', 'password', 'userA', 'userB', )
    write_only_fields = ('password',)

  @transaction.commit_manually 
  def restore_object(self, attrs, instance = None):

     try:
         user = User.objects.create_user(email = attrs.get('email'), password =   attrs.get('password'))
        modela = ModelA(user =user, name = attrs.get('name'))
        modela.save()
        transaction.commit()
        return User(email = attrs.get('email'))
    except Exception ,e:
        transaction.rollback()
        print repr(e) 

JSON我传递

data = {'email':'123@gmail.com,
        'password' : 'dummy',
        'userA' :   {'name' :'123'},
        'userB':{'type':1,'cost':'100'}

无论什么时候发出POST请求,都可以使用' attrs'只获得电子邮件和密码而不是userA和userB,为什么?如何在相应的表中串行反序列化和创建数据。

1 个答案:

答案 0 :(得分:1)

在您的视图中尝试此操作

from django.core.serializers.json import DjangoJSONEncoder
import json

response = json.dumps(data,cls=DjangoJSONEncoder)
return HttpResponse(response, mimetype="application/json")

并且在成功功能中,您可以使用

进行访问
usera_name = response.userA.name
userb_type = response.userB.type
userb_cost = response.userB.cost