Question

我有一个代码在java中读取受保护的Excel，但该代码给了我错误。我的java代码。

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.security.GeneralSecurityException;
import java.util.Iterator;

import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.crypt.Decryptor;
import org.apache.poi.poifs.crypt.EncryptionInfo;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;

public class REadProtectedExcel {
    public static void main(String[] args) {
        String fname = "D:/Vijay/BRS_docs/10168/20.11.2014/20.11.2014/JCR_30.12.14_I Pay.xls";
        try {
            POIFSFileSystem fs = new POIFSFileSystem(new FileInputStream(fname));
            EncryptionInfo info = new EncryptionInfo(fs);
            Decryptor d = Decryptor.getInstance(info);
            if (d.verifyPassword("vijay")) {
                System.out.println("Password correct");
                FileInputStream fis = new FileInputStream(fname);
                HSSFWorkbook workbook = new HSSFWorkbook(fis);
                HSSFSheet sheet = workbook.getSheetAt(0);
                Iterator rowIter = sheet.rowIterator();
                while (rowIter.hasNext()) {
                    HSSFRow myRow = (HSSFRow) rowIter.next();
                    Iterator cellIter = myRow.cellIterator();
                    while (cellIter.hasNext()) {
                        String cellvalue = "";
                        HSSFCell myCell = (HSSFCell) cellIter.next();
                        if (myCell.getCellType() == HSSFCell.CELL_TYPE_STRING) {
                            cellvalue = myCell.getStringCellValue();
                        } else if (myCell.getCellType() == HSSFCell.CELL_TYPE_NUMERIC) {
                            cellvalue = "" + myCell.getNumericCellValue();
                        } else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BOOLEAN) {
                            cellvalue = "" + myCell.getBooleanCellValue();
                        } else if (myCell.getCellType() == HSSFCell.CELL_TYPE_FORMULA) {
                            cellvalue = "" + myCell.getCellFormula();
                        } else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BLANK) {
                            cellvalue = "";
                        }
                        System.out.println("cellvalue--" + cellvalue);
                    }
                }
            } else {
                System.out.println("Password wrong");
            }
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (GeneralSecurityException e) {
            e.printStackTrace();
        }
    }
}

此代码会出现以下错误。

java.io.FileNotFoundException: no such entry: "EncryptionInfo"
    at org.apache.poi.poifs.filesystem.DirectoryNode.getEntry(DirectoryNode.java:375)
    at org.apache.poi.poifs.filesystem.DirectoryNode.createDocumentInputStream(DirectoryNode.java:177)
    at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:45)
    at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:39)
    at com.test.arrayList.REadProtectedExcel.main(REadProtectedExcel.java:22)

我正在使用poi3.9 jar，xmlbeans-2.3.0jar，poi-ooml-3.6
我没有得到这个问题。提前谢谢。
或者请分享另一种方式来阅读.xls文件。

Answer 1

Apache POI provides documentation on Encryption on the website。如果您转到Apache POI homepage并查看左侧菜单顶部附近，则会在Encryption Support下找到该链接。我强烈建议你阅读它！

正如您所看到的，您编写的代码是针对加密.xlsx文件的，这些文件使用了一种非常不同的方式来保护文件到较旧的.xls文件

正如文档所解释的那样，对于受密码保护的.xls文件，您需要做的就是：

String myPassword = "password";
org.apache.poi.hssf.record.crypto.Biff8EncryptionKey.setCurrentUserPassword(myPassword);
HSSFWorkbook wb = new HSSFWorkbook(stream);

如何在java中读取受密码保护的.xls文件？

1 个答案: