Question

看，我把它作为mySQL中的数据。表名是＆＃34; schedule＆＃34;

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Mapel | Kelas | Tanggal |那抹|状态

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BHS。印度|| 1A || 2015-01-14 ||阿迪|| x

BHS。印度|| 1A || 2015-01-14 || Ani || x

BHS。印度|| 1A || 2015-01-14 ||思思|| -

BHS。印度|| 1A || 2015-01-14 ||塔拉|| -

BHS。印度|| 1A || 2015-01-14 || Wina || x

数学|| 1A || 2015-01-15 ||阿迪|| x

数学|| 1A || 2015-01-15 || Ani || -

数学|| 1A || 2015-01-15 ||思思|| -

数学|| 1A || 2015-01-15 ||塔拉|| -

数学|| 1A || 2015-01-15 || Wina || x

BHS。印度|| 1A || 2015-01-15 ||阿迪|| x

BHS。印度|| 1A || 2015-01-15 || Ani || -

BHS。印度|| 1A || 2015-01-15 ||思思|| -

BHS。印度|| 1A || 2015-01-15 ||塔拉|| -

BHS。印度|| 1A || 2015-01-15 || Wina || x

现在我想制作一个表格依赖于＆＃34; MAPEL＆＃34;和＃34; KELAS＆＃34; 如果我选择Mapel =＆＃39; Bhs。印度＆＃39;和KELAS =＆＃39; 1A＆＃39;会显示这样的表

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Kelas | Nama | 2015-01-14 | 2015-01-15 |

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1A ||阿迪|| x || X

1A || Ani || x || -

1A ||思思|| - || -

1A || Tara || - || -

1A || Wina || x || X

Answer 1

如果你想根据表中的实际内容动态获取日期，那么唯一可行的方法就是使用动态SQL

SET @sql = NULL;

SELECT GROUP_CONCAT(DISTINCT CONCAT(
  'MAX(CASE WHEN tanggal = ''', tanggal, 
  ''' THEN status END) `', tanggal, '`'))  
  INTO @sql
  FROM schedule 
 WHERE mape = 'Bhs. Indo'
   AND kelas = '1A'
 ORDER BY tanggal;

SET @sql = CONCAT(
  'SELECT kelas, nama, ', @sql, 
  '  FROM schedule ',
  ' WHERE mape = ''Bhs. Indo''',
  '   AND kelas = ''1A''',
  ' GROUP BY kelas, nama'
);

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

输出：

| KELAS | NAMA | 2015-01-14 | 2015-01-15 |
|-------|------|------------|------------|
|    1A |  Adi |          x |          x |
|    1A |  Ani |          x |          - |
|    1A | Sisi |          - |          - |
|    1A | Tara |          - |          - |
|    1A | Wina |          x |          x |

这是 SQLFiddle 演示

您可以将其包装在存储过程中，以简化客户端代码中的操作。

如何将行转置为多列？

1 个答案: