以下是红绿灯控制器的简单代码。它根据计数器值循环通过状态。但是我希望它在第一个状态下再保持10秒，当按下任何想法时我会怎么做。
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use ieee.std_logic_unsigned.all;
entity TLC is
Port (
Trafficlights: out STD_LOGIC_Vector (5 downto 0);
Clck : in STD_LOGIC;
Reset : in STD_LOGIC;
P_B : in STD_LOGIC);
end TLC;
architecture Behavioral of TLC is
type state_type is (st0_R1_G2, st1_R1_A1_A2, st2_G1_R2, st3_A1_R2_A2);
signal state: state_type;
signal count : std_logic_vector (3 downto 0);
constant sec10 : std_logic_vector ( 3 downto 0) := "1010";
constant sec2 : std_logic_vector (3 downto 0 ) := "0010";
constant sec16: std_logic_vector (3 downto 0 ) := "1111";
begin
process (Clck,Reset)
begin
if Reset='1' then
state <= st0_R1_G2; --reset to initial state
count <= X"0"; -- reset counter
elsif Clck' event and Clck = '1' then --rising edge
case (state) is ---state transitions
when st0_R1_G2 =>
if count < sec10 then
state <= st0_R1_G2;
count <= count + 1;
else
state <= st1_R1_A1_A2;
count <= X"0";
end if;
when st1_R1_A1_A2 =>
if count < sec2 then
state <= st1_R1_A1_A2;
count <= count + 1;
else
state <= st2_G1_R2;
count <= X"0";
end if;
when st2_G1_R2 =>
if count < sec10 then
state <= st2_G1_R2;
count <= count + 1;
else
state <= st3_A1_R2_A2;
count <= X"0";
end if;
when st3_A1_R2_A2 =>
if count < sec2 then
state <= st3_A1_R2_A2;
count <= count + 1;
else
state <=st0_R1_G2;
count <= X"0";
end if;
when others =>
state <= st0_R1_G2;
end case;
end if;
end process;
OUTPUT_DECODE: process (state)
begin
case state is
when st0_R1_G2 => Trafficlights <= "100001"; -- Traffic Red 1, Pedestrian Green 1
when st1_R1_A1_A2 => Trafficlights <= "110010";
when st2_G1_R2 => Trafficlights <= "001100";
when st3_A1_R2_A2 => Trafficlights <= "010110";
when others => Trafficlights <= "100001";
end case;
end process;
end Behavioral;
答案 0 :(得分：0)
我还没有模拟过这个。
这个想法是将count计数器延长一点，包含额外的10秒。输入p_b用于异步设置按钮事件锁存器，用于启动扩展计数，可能允许人行横道流量在前10秒内遍历。
由JK触发器（crosstime）控制。这里值得注意的特征应该是仅在延长的20秒周期的前10秒启用交叉步行。你没有得到许可，无法跨越。
所有这一切都假定您的按钮是按需行人过路处请求，您不能解释您的州名和灯光。
我猜你想要用crosstime给行人绿灯做准备。
（如果这不起作用或者不是你想要的，你就得到了你付出的代价。）
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity tlc is
port (
trafficlights: out std_logic_vector (5 downto 0);
clck: in std_logic;
reset: in std_logic;
p_b: in std_logic
);
end entity tlc;
architecture behavioral of tlc is
type state_type is (st0_r1_g2, st1_r1_a1_a2, st2_g1_r2, st3_a1_r2_a2);
signal state: state_type;
signal count: std_logic_vector (4 downto 0) ; -- (3 downto 0);
signal pb_event: std_logic;
signal crosstime: std_logic; -- JK FF
constant sec10 : std_logic_vector (4 downto 0) := "01010"; -- ( 3 downto 0) := "1010";
constant sec2 : std_logic_vector (4 downto 0) := "00010"; -- (3 downto 0 ) := "0010";
-- constant sec16: std_logic_vector (4 downto 0) := "01111"; -- (3 downto 0 ) := "1111";
constant sec20: std_logic_vector (4 downto 0) := "10100"; -- new
begin
process (clck, reset, p_b) -- added push button
begin
if p_b = '1' and reset = '0' then -- asynch set for push button
pb_event <= '1';
end if;
if reset = '1' then
state <= st0_r1_g2; -- reset to initial state
count <= (others => '0'); -- reset counter
pb_event <= '0';
crosstime <= '0';
elsif clck' event and clck = '1' then -- rising edge
if pb_event = '1' and count = "00000" then -- J input
crosstime <= '1';
end if;
case (state) is -- state transitions
when st0_r1_g2 =>
if (crosstime = '0' and count < 20) or
(crosstime = '1' and count < sec10) then
state <= st0_r1_g2;
count <= count + 1;
else
state <= st1_r1_a1_a2;
count <= "00000"; -- x"0";
if crosstime = '1' then -- K input
crosstime <= '0';
pb_event <= '0';
end if;
end if;
when st1_r1_a1_a2 =>
if count < sec2 then
state <= st1_r1_a1_a2;
count <= count + 1;
else
state <= st2_g1_r2;
count <= (others => '0');
end if;
when st2_g1_r2 =>
if count < sec10 then
state <= st2_g1_r2;
count <= count + 1;
else
state <= st3_a1_r2_a2;
count <= (others => '0');
end if;
when st3_a1_r2_a2 =>
if count < sec2 then
state <= st3_a1_r2_a2;
count <= count + 1;
else
state <=st0_r1_g2;
count <= (others => '0');
end if;
when others =>
state <= st0_r1_g2;
end case;
end if;
end process;
output_decode:
process (state)
begin
case state is
when st0_r1_g2 => trafficlights <= "100001"; -- traffic red 1, pedestrian green 1
when st1_r1_a1_a2 => trafficlights <= "110010";
when st2_g1_r2 => trafficlights <= "001100";
when st3_a1_r2_a2 => trafficlights <= "010110";
when others => trafficlights <= "100001";
end case;
end process;
end architecture behavioral;
<小时/> * ...香港专业教育学院试图合成这个，我得到并且错误说＆＃34;信号pb_event无法合成，错误的同步描述。当前软件版本不支持用于描述同步元素（寄存器，内存等）的描述样式。＆＃34;你有什么想法是因为它的异步并且与其他同步设计不兼容吗？*
在不知道供应商抱怨pb_even的情况下，它会牵扯我们的手。
似乎抱怨在pb_event上同时进行异步设置和异步重置。删除异步重置可能会解决问题（需要使用该集来告诉我们有人想要使用人行横道）。
让我们将pb_event触发器移出当前进程以使其可用。仅使用set输入的结果是重置将设置pb_event并导致第一次crosswalk事件。
注意我仍然不了解交通灯，并且我在状态st0_r1_g2中进行的修改预计在较长的20秒间隔的前10秒内启用人行横道灯。这不包括在内。
此外，您可以简单地将计数与最终计数进行比较，＆＃34; / =＆＃34;而不是＆＃34;＆lt;＆＃34;这可能导致计数比较逻辑减少。这可能发生，因为count总是介于0和结束计数之间。平等比量级比较容易得多。我也没有进行这些更改（并且我很想为计数终端值设置单独的识别器）。
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity tlc is
port (
trafficlights: out std_logic_vector (5 downto 0);
clck: in std_logic;
reset: in std_logic;
p_b: in std_logic
);
end entity tlc;
architecture behavioral of tlc is
type state_type is (st0_r1_g2, st1_r1_a1_a2, st2_g1_r2, st3_a1_r2_a2);
signal state: state_type;
signal count: std_logic_vector (4 downto 0) ;
signal pb_event: std_logic;
signal crosstime: std_logic; -- JK FF
constant sec10 : std_logic_vector (4 downto 0) := "01010";
constant sec2 : std_logic_vector (4 downto 0) := "00010";
constant sec20: std_logic_vector (4 downto 0) := "10100";
begin
pbevent:
process (clck, reset, p_b)
begin
if p_b = '1' or reset = '1' then -- async set for push button
pb_event <= '1'; -- reset will give crosswalk event
elsif clck'event and clck = '1' then
if state = st0_r1_g2 and
(( crosstime = '1' and count = sec10) or count = sec20) then
pb_event <= '0';
end if;
end if;
end process;
unlabelled:
process (clck, reset)
begin
if reset = '1' then
state <= st0_r1_g2; -- reset to initial state
count <= (others => '0'); -- reset counter
crosstime <= '0';
elsif clck'event and clck = '1' then
if pb_event = '1' and count = "00000" then -- J input
crosstime <= '1';
end if;
case (state) is
when st0_r1_g2 =>
if (crosstime = '0' and count < sec20) or
(crosstime = '1' and count < sec10) then
state <= st0_r1_g2;
count <= count + 1;
else
state <= st1_r1_a1_a2;
count <= "00000";
if crosstime = '1' then -- K input
crosstime <= '0';
end if;
end if;
when st1_r1_a1_a2 =>
if count < sec2 then
state <= st1_r1_a1_a2;
count <= count + 1;
else
state <= st2_g1_r2;
count <= (others => '0');
end if;
when st2_g1_r2 =>
if count < sec10 then
state <= st2_g1_r2;
count <= count + 1;
else
state <= st3_a1_r2_a2;
count <= (others => '0');
end if;
when st3_a1_r2_a2 =>
if count < sec2 then
state <= st3_a1_r2_a2;
count <= count + 1;
else
state <=st0_r1_g2;
count <= (others => '0');
end if;
when others =>
state <= st0_r1_g2;
end case;
end if;
end process;
output_decode:
process (state)
begin
case state is
when st0_r1_g2 => trafficlights <= "100001"; -- traffic red 1, pedestrian green 1
when st1_r1_a1_a2 => trafficlights <= "110010";
when st2_g1_r2 => trafficlights <= "001100";
when st3_a1_r2_a2 => trafficlights <= "010110";
when others => trafficlights <= "100001";
end case;
end process;
end architecture behavioral;
状态st0_r1_g2中找到的条件已折叠为单独写入＆＃39; 0＆＃39;到了pb_event触发器。您可能会预计任何时间count = sec20应该清除触发器。