Question

我有两张桌子;

dbo.Users：

user_id user_name   gender   has_phone
--------------------------------------
1       admin       Male     true
2       UserA       Male     false
3       UserB       Female   true

和dbo.Filterby：

id  name        filterid    filtervalue 
---------------------------------------
1   All         NULL        -1              
2   Males       gender      Male            
3   Females     gender      Female  
4   Phone       has_phone   true
5   NoPhone     has_phone   false

我需要根据来自filterby的查询结果选择所有患者，例如我希望所有男性都返回：

SELECT 
    [user_id], [user_name] 
FROM 
    dbo.Users
WHERE 
    (SELECT filterid FROM dbo.Filterby WHERE id = 2) = (SELECT filtervalue FROM dbo.Filterby WHERE id = 2)

这应该更通用，所以我可以传入任何Filterby.id，它将返回正确的结果。但基本上，我真的只需要知道如何选择使用另一个查询的结果作为列标识符。

我该怎么做？

感谢。

Answer 1

根据我的经验，使用动态SQL将是最简单的方法。看看下面的例子。基本上我认为你想要使用变量和一些动态SQL来分割它。

DECLARE @Table_Name VARCHAR(1000) /*Would actually be an input parameter in  
our SP.*/

DECLARE @Statement VARCHAR(1000) /*Declaration of our SQL statement to 

execute.*/

SET @Table_Name = 'ErrorLog' /*The value for our input parameter*/

SET @Statement = 'SELECT * FROM ' + '[dbo].[' + @Table_Name + ']'; 

/*Dynamically creating the SQL statement with our table_name variable.*/

EXEC (@Statement); /*We execute the @statement to get our results.*/

上面接受一个声明的变量，然后根据它执行一个语句。根据您的需要，您也可以使用变量。您也可以在传入filtervalue的存储过程中查看此操作。

Answer 2

您可以使用CROSS JOIN

执行此操作

SELECT 
    user_id, user_name, gender, has_phone 
FROM (
    SELECT 
        u.user_id,u.user_name, u.gender,u.has_phone, 
        CASE ISNULL(f.filterid,'')
            WHEN '' THEN '-1'
            WHEN 'gender' THEN u.gender
            WHEN 'has_phone' THEN u.has_phone
        END AS val,
        f.filtervalue
    FROM users AS u
        CROSS JOIN Filterby AS f
    WHERE f.id=4  -- here id of filter
) AS m
WHERE
    val=filtervalue

如果您需要使用两个或多个字段的过滤，例如此过滤表

id  name        filterid    filtervalue 
---------------------------------------
1   All         NULL        -1              
2   Males       gender      Male            
3   Females     gender      Female  
4   PhoneMales  has_phone   true
4   PhoneMales  gender      Male
5   NoPhone     has_phone   false

然后你可以使用enchanted版本的查询

SELECT 
    m2.user_id, u2.user_name, u2.gender, u2.has_phone
FROM (
    SELECT user_id
    FROM (  
        SELECT
            u.user_id, 
            CASE ISNULL(f.filterid,'')
                WHEN '' THEN '-1'
                WHEN 'gender' THEN u.gender
                WHEN 'has_phone' THEN u.has_phone
            END AS val,
            f.filtervalue
        FROM users AS u
            CROSS JOIN Filterby AS f
        WHERE f.id=4  -- here id of filter
    ) AS m
    WHERE val=filtervalue 
    GROUP BY user_id
    HAVING COUNT(*)=(
        SELECT COUNT(*) FROM Filterby WHERE id=4 -- here must be the same filter id as above 
    )
) AS m2 
    INNER JOIN users AS u2
      ON m2.user_id=u2.user_id

Answer 3

declare @a nvarchar(30)

declare @table table (a nvarchar(30))

insert into @table values('select ''''''a''''''')

select @a=a from @table

exec(@a)

在第四行，您正在存储 - ＆gt;选择＆＃39; a＆＃39;变量@a 在第五行，你正在执行@a

在此，您将onte表中的数据分配给某个变量并使用exec（）命令执行该数据。

如果有帮助，请将此标记为答案或投票

SELECT WHERE（列名是另一个查询的结果）

3 个答案: