Question

我想继续遍历文本文件，直到满足循环中的当前条件。

这是示例文本：

10-01   N/A
10-02   N/A
10-03   N/A
10-04   N/A
10-05   N/A
10-06   N/A
10-07   N/A
10-08   N/A
10-09   N/A
10-10   N/A
10-11   N/A
10-12   N/A
===04===...... # Skip line until '01' is found
===12===...... # Skip line until '01' is found
05-01   N/A
05-02   N/A
05-03   N/A
05-04   N/A
05-05   N/A
05-06   N/A
===08===...... # Skip line until '07' is found
===11===...... # Skip line until '07' is found
05-07   N/A
05-08   N/A
05-09   N/A
05-10   N/A
05-11   N/A
05-12   N/A

这是我正在尝试的while循环：

x = 1
with open(loc_path + 'SAMPLEDATA.TXT', 'rb') as textin:
    for line in textin:
        while x < 13:
            if line[3:].startswith(str(x).zfill(2)):
                print '%r' % line
            else:
                x = 1 # Restart loop
            x += 1

除了使用while循环，如果使用while循环不正确，还有另一种方法可以实现吗？

谢谢

Answer 1

您希望：只有当您找到要查找的行时才会递增计数器，并在每次点击13时重置该计数器

x = 1
with open(loc_path + 'SAMPLEDATA.TXT', 'rb') as textin:
    for line in textin:
        if line[3:].startswith(str(x).zfill(2)):
            print '%r' % line
            x += 1
        if x >= 13:
            x = 1  # reset counter

Answer 2

您希望将while x < 13更改为if语句，以有条件地停止for循环。如，

x = 1
with open(loc_path + 'SAMPLEDATA.TXT', 'rb') as textin:
    for line in textin:
        if line[3:].startswith(str(x).zfill(2)):
            print '%r' % line
        else:
            x = 1 # Restart counter
        x += 1
        if x >= 13:
            break # Stop reading

python迭代文本文件，直到满足条件

2 个答案: