Question

我想打开从一台服务器到另一台服务器的ssh连接，因此尝试使用pxssh模块。运行以下代码时出现以下错误：

我的代码：

import pxssh
s = pxssh.pxssh()
if not s.login ('host','user','password'):
    print "SSH session failed on login."
else:
    print "SSH session login successful"
    s.sendline ('ls -ltr')
    s.logout()

在运行此代码时，我得到以下内容：

Traceback (most recent call last):
  File "ssh.py", line 20, in <module>
    if not s.login ('135.250.138.207','astro','astro'):
  File "/usr/lib/python2.6/site-packages/pxssh.py", line 243, in login
    if not self.synch_original_prompt():
  File "/usr/lib/python2.6/site-packages/pxssh.py", line 134, in synch_original_prompt
    self.read_nonblocking(size=10000,timeout=1) # GAS: Clear out the cache before getting the prompt
  File "/usr/lib/python2.6/site-packages/pexpect.py", line 824, in read_nonblocking
    raise TIMEOUT ('Timeout exceeded in read_nonblocking().')
pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().

如何成功运行上述代码？

Answer 1

self.sendline()

在第134行之前添加此内容，在File＆＃34; /usr/lib/python2.6/site-packages/pxssh.py" 它按预期工作。

如何在python中使用pxssh模块打开ssh连接

1 个答案: