Python SyntaxError:无效的语法elif语句

时间:2015-01-12 10:52:01

标签: python syntax-error

所以我对python很新,我熟悉Java,C和Ruby。

我尝试为Kali编译脚本以修复wifi设备的RFkill问题,因为Kali没有RFKill。

#!/usr/bin/python
# replacement for rfkill util, which is missing in kali
# By: Geist

from sys import argv

if(argv[1] == "unblock"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
x.seek(0)
x.write('0')

elif(argv[1] == "block"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
x.seek(0)
x.write('1')


print("interface %s %sed" % (argv[2], argv[1]))

我没有写这个但是我试图运行它并且我一直在获取一个语法错误:elif下的语法无效(argv [1] ==“block”):

我认为这与不正确的缩进有关,如果有人能够让我知道我做错了什么以及为什么那会很棒!

3 个答案:

答案 0 :(得分:2)

缩进在Python中很重要。您的if区块与elif区块之间有缩进线。这些将导致SyntaxError,因为您实际上没有elif阻止if

缩进您的行,使其与if块匹配,或使用第二个if语句而不是elif。看看你的代码,我想你会想要缩进它们,否则你会得到NameErrors。在这种情况下,它变成:

#!/usr/bin/python
# replacement for rfkill util, which is missing in kali
# By: Geist

from sys import argv

if(argv[1] == "unblock"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
    x.seek(0)
    x.write('0')

elif(argv[1] == "block"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
    x.seek(0)
    x.write('1')


print("interface %s %sed" % (argv[2], argv[1]))

答案 1 :(得分:0)

代码中的缩进问题,根据您的算法进行更改 -

例如

#!/usr/bin/python
# replacement for rfkill util, which is missing in kali
# By: Geist

from sys import argv

if(argv[1] == "unblock"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
    x.seek(0)
    x.write('0')
elif(argv[1] == "block"):
    x = open("/sys/class/rfkill/rfkill%s/soft" % argv[2], "w")
    x.seek(0)
    x.write('1')


print("interface %s %sed" % (argv[2], argv[1]))

答案 2 :(得分:0)

这是该脚本的稍微清洁版本。

#! /usr/bin/env python

from sys import argv

def main():
    try:
        cmd = ("unblock", "block").index(argv[1])
    except ValueError:
        print("Bad command: %s" % argv[1])
        exit(1)

    fname = "/sys/class/rfkill/rfkill%s/soft" % argv[2]
    with open(fname, "w") as f:
        f.seek(0)
        f.write(str(cmd))

    print("Interface %s %sed" % (argv[2], argv[1]))


if __name__ == "__main__":
    main()
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