Question

如何从日期时间选择器值显示年龄，月，日。例如：

Datetimepicker value = #1/11/2014#
Today = #1/12/2015#.

最终结果将是＆＃34; 1年，0个月，1天（S）和＃34;。但是获得该结果不仅仅是减去DateTime.Year值等等。有人知道数学公式或数学计算吗？

Answer 1

这是一个DateTimeSpan类型，它返回一个像TimeSpan这样的对象，代表两个日期之间经过的年，月，日。它循环通过时间单位来递增它们，直到较小的日期与较大的日期匹配。然后，在新的DateTimeSpan对象中返回结果增量。

Public Structure DateTimeSpan

    Private _Years As Integer
    Public ReadOnly Property Years As Integer
        Get
            Return _Years
        End Get
    End Property

    Private _Months As Integer
    Public ReadOnly Property Months As Integer
        Get
            Return _Months
        End Get
    End Property

    Private _Days As Integer
    Public ReadOnly Property Days As Integer
        Get
            Return _Days
        End Get
    End Property

    Private _Hours As Integer
    Public ReadOnly Property Hours As Integer
        Get
            Return _Hours
        End Get
    End Property

    Private _Minutes As Integer
    Public ReadOnly Property Minutes As Integer
        Get
            Return _Minutes
        End Get
    End Property

    Private _Seconds As Integer
    Public ReadOnly Property Seconds As Integer
        Get
            Return _Seconds
        End Get
    End Property

    Private _MilliSeconds As Integer
    Public ReadOnly Property MilliSeconds As Integer
        Get
            Return _MilliSeconds
        End Get
    End Property

    ' the ctor for the result
    Private Sub New(y As Integer, mm As Integer, d As Integer,
                    h As Integer, m As Integer, s As Integer,
                    ms As Integer)
        _Years = y
        _Months = mm
        _Days = d
        _Hours = h
        _Minutes = m
        _Seconds = Seconds
        _MilliSeconds = ms
    End Sub

    ' private time unit tracker when counting
    Private Enum Unit
        Year
        Month
        Day
        Complete
    End Enum

    Public Shared Function DateSpan(dt1 As DateTime, 
                                    dt2 As DateTime) As DateTimeSpan
        ' we dont do negatives
        If dt2 < dt1 Then
            Dim tmp = dt1
            dt1 = dt2
            dt2 = tmp
        End If

        Dim thisDT As DateTime = dt1
        Dim years As Integer = 0
        Dim months As Integer = 0
        Dim days As Integer = 0

        Dim level As Unit = Unit.Year
        Dim span As New DateTimeSpan()

        While level <> Unit.Complete
            Select Case level
                ' add a year until it is larger;
                ' then change the "level" to month
                Case Unit.Year
                    If thisDT.AddYears(years + 1) > dt2 Then
                        level = Unit.Month
                        thisDT = thisDT.AddYears(years)
                    Else
                        years += 1
                    End If

                Case Unit.Month
                    If thisDT.AddMonths(months + 1) > dt2 Then
                        level = Unit.Day
                        thisDT = thisDT.AddMonths(months)
                    Else
                        months += 1
                    End If

                Case Unit.Day
                    If thisDT.AddDays(days + 1) > dt2 Then
                        thisDT = thisDT.AddDays(days)
                        Dim thisTS = dt2 - thisDT
                        ' create a new DTS from the values caluclated
                        span = New DateTimeSpan(years, months, days, thisTS.Hours,
                                                thisTS.Minutes, thisTS.Seconds,
                                    thisTS.Milliseconds)
                        level = Unit.Complete
                    Else
                        days += 1
                    End If
            End Select
        End While

        Return span

    End Function

End Structure

用法：

Dim dts As DateTimeSpan = DateTimeSpan.DateSpan(#2/11/2010#, #10/21/2013#)
Console.WriteLine("{0} Yrs, {1} Months and {2} Days",
                           dts.Years.ToString, dts.Months.ToString, dts.Days.ToString)

这将得到相同的结果：

Dim dtStart As DateTime = #2/11/2010#
Dim dtEnd As new DateTime(2013, 10, 21)
' this is NOT a date and wont work:
Dim myDt = "2/11/2010"             ' its a string!

Dim dts As DateTimeSpan = DateTimeSpan.DateSpan(dtEnd, dtStart)

结果：3 Yrs, 8 Months and 10 Days

注意：
- 它仅适用于正确的DateTime类型，而不适用于看起来像日期的字符串。使用文字（#...#）或DateTime变量。使用DateTimePicker时，请使用.Value而不是.Text - 它不做负值，因此传递的值的顺序无关紧要 - 计算时，它会增加DateTime变量，因此，它应该正确计算闰日

这是基于我很久以前在博客中找到的一些C＃代码（或者甚至是来自SO的答案或问题）。暂时不能发现它引用原文。

Answer 2

这种方法非常简单直接不需要创建循环和类属性。

这适用于真实Date类型和Strings日期：

   'Date Picker Value
    Dim dBirthDate As Date = "#01/11/2014#"

    'Today
    Dim dToday As Date = "#01/12/2015#"

    Dim dBirthDay As Date

    Dim sYears As String
    Dim sDays As String
    Dim sMonths As String
    Dim sResults As String


    sYears = DateDiff(DateInterval.Year, dBirthDate, dToday)

    dBirthDay = dBirthDate.AddYears(sYears)

    sMonths = DateDiff(DateInterval.Month, dBirthDay, dToday)

    sDays = DateDiff(DateInterval.Day, dBirthDay, dToday)


    sResults = sYears & " Year " & sMonths & " Months " & sDays & " Day(s)"

示例结果：1年0个月1天

Answer 3

此方法使用循环向后工作，但我相信这是唯一准确的方法，并使值始终正确。这是因为它比你想象的要复杂得多 - 你需要调整闰年等等。

''' <summary>
''' Finds the Years Months and Days Span between two dates
''' </summary>
''' <param name="fromDate"></param>
''' <param name="toDate"></param>
''' <returns>A String formatted as i Years j Months k Days</returns>
''' <remarks></remarks>
Public Shared Function GetDateSpanText(ByVal fromDate As DateTime, Optional toDate As DateTime = Nothing) As String
        Dim years As Integer = 0, months As Integer = 0, days As Integer = 0
        If toDate = Nothing Then toDate = DateTime.Now

        Do Until toDate.AddYears(-1) < fromDate
            years += 1
            toDate = toDate.AddYears(-1)
        Loop

        Do Until toDate.AddMonths(-1) < fromDate
            months += 1
            toDate = toDate.AddMonths(-1)
        Loop

        Do Until toDate.AddDays(-1) < fromDate
            days += 1
            toDate = toDate.AddDays(-1)
        Loop

        Return String.Format("{0} Year(s) {1} Month(s) {2} Day(s)", years, months, days)
End Function

用法：

Debug.WriteLine(GetDateSpanText(#1/11/2014#))

打印：

1 Year(s) 0 Month(s) 1 Day(s)

Answer 4

您必须添加此内容才能获得完整的结果： sDays =（DateDiff（DateInterval.Day，dBirthDay，dToday）） - sMonths * 30

获取经过一段时间的年，月，日（DateTime）

4 个答案:

用法：