暂停/恢复线程的pthreads：＆＃34; mutex-＆gt; __ data .__ owner == 0＆＃34;

Question

我有一个多线程程序。由于我想不时重置状态，我想暂停所有线程一段时间。为此，我已经实现了此问题的解决方案之一：What is the best solution to pause and resume pthreads?

pthread_mutex_t suspend_mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t resume_cond = PTHREAD_COND_INITIALIZER;

int suspend_flag = 0;

void suspend_threads()
{ // tell the thread to suspend
    pthread_mutex_lock(&suspend_mutex);
    suspend_flag = 1;
    pthread_mutex_unlock(&suspend_mutex);
}

void resume_threads()
{ // tell the thread to resume
    pthread_mutex_lock(&suspend_mutex);
    suspend_flag = 0;
    pthread_cond_broadcast(&resume_cond);
    pthread_mutex_unlock(&suspend_mutex);
}

void check_suspend()
{ // if suspended, suspend until resumed
    pthread_mutex_lock(&suspend_mutex);
    while (suspend_flag != 0) pthread_cond_wait(&resume_cond, &suspend_mutex);
    pthread_mutex_unlock(&suspend_mutex);
}

当线程处于方便状态时，线程会非常频繁地调用

check_suspend。

现在的问题是我收到断言失败：

 pthread_mutex_lock.c:62: __pthread_mutex_lock: Assertion `mutex->__data.__owner == 0' failed.
[New LWP 1981]

Program received signal SIGABRT, Aborted.
[Switching to LWP 1981]
0x0151f5b0 in raise (sig=6) at ../nptl/sysdeps/unix/sysv/linux/raise.c:67
67      ../nptl/sysdeps/unix/sysv/linux/raise.c: No such file or directory.
        in ../nptl/sysdeps/unix/sysv/linux/raise.c
(gdb) up
#1  0x014e0f90 in abort () at abort.c:121
121     abort.c: No such file or directory.
        in abort.c
(gdb) up
#2  0x014db638 in __assert_fail (assertion=0x1a1692c "mutex->__data.__owner == 0",  file=0x1a16d90 "pthread_mutex_lock.c", line=62, f
81      assert.c: No such file or directory.
        in assert.c
(gdb) up
#3  0x014c82a8 in __pthread_mutex_lock (mutex=0x1fcdc9c) at pthread_mutex_lock.c:62
62      pthread_mutex_lock.c: No such file or directory.
        in pthread_mutex_lock.c
(gdb) up
#4  0x014b0694 in check_suspend () at     /home/data/programming/broadcom/ssdk/src/customer/epfl_vdp.c:1736
warning: Source file is more recent than executable.
1736        pthread_mutex_lock(&suspend_mutex);
(gdb) p suspend_mutex
$1 = {
  __data = {
    __lock = 2, 
    __count = 0, 
    __owner = 0, 
    __kind = 0, 
    __nusers = 0, 
    {
      __spins = 0, 
      __list = {
        __next = 0x0
      }
    }
  }, 
  __size = "\000\000\000\002", '\000' <repeats 19 times>, 
  __align = 2
}

搜索只提出了一个问题，即一个人试图解锁他没有拥有的锁，但据我所知，代码并非如此。