<?php
require_once 'init.php';
if(isset($_POST['username'], $_POST['password'])) {
$extractInfoUser = $db->prepare("
SELECT * FROM user
WHERE username = :username
");
$extractInfoUser->execute([
'username' => $_POST['username']
]);
$users = $extractInfoUser->rowCount() ? $extractInfoUser : [] ;
foreach ($users as $user) {
if ($user['username'] = null) {
die("There is no username like this !");
} else {
echo "You are not able to register under this username !";
}
}
}
?>
问题是我得到了结果没有! 请帮助因为我找不到这个错误!我不知道它是什么!
答案 0 :(得分:3)
您的IF声明错误,您正在设置而不是检查。
if ($user['username'] = null) {
你应该这样做:
if ($user['username'] == null) {
您忘记使用double =运算符,而不是检查您是否将$ user [&#39; username&#39;]设置为false。
答案 1 :(得分:3)
您执行了分配而不是比较,因此更改此if语句:
if ($user['username'] = null)
到此:
if ($user['username'] == null)
//^^ See here 2x '='