Question

<?xml version="1.0" encoding="UTF-8"?>
<suite name="Test Suite Name" parallel="none">
<listeners>
    <listener class-name="testng.MyListener"></listener>
</listeners>
  <test name="Test localhost">
    <parameter name="Browser" value="chrome"/> <!-- chrome or firefox or IE or Android Native-->
    <parameter name="url" value='' /> <!-- URL of the webpage you want to test -->
    <parameter name="CSV" value="data.csv"/> <!-- Location of the CSV file that you want to run tests with -->
    <parameter name="resultLocation" value="C:\Users\xvdf\Desktop\testmap"/> <!-- TestNG will create two folders in this location, screenshots and test-output-datestamp -->
    <parameter name="runType" value="baseline" /> <!--  actual or baseline . baseline = first run. actual is second run, to do a compare for example -->
    <classes>
      <class name="testng.runTest"></class>
    </classes>
  </test> <!-- Test CAN YOU SEE THIS?-->
</suite> <!-- Suite end of suite -->

我正在尝试编辑此XML，因此我可以更改2个参数，resultLocation和runType。到目前为止，我已经尝试过使用DocumentBuilder的一些东西，但是我无法通过它来查找属性。这是我到目前为止尝试过的代码。第一部分有效，我可以进入测试元素。

package testng;

import java.io.File;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class ModifyXMLFile {

    public static void main(String argv[]) {

       try {
        String filepath = "testng.xml";
        DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
        Document doc = null;
        try {
            doc = docBuilder.parse(filepath);
        } catch (SAXException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        // Get the root element
        Node suite = doc.getFirstChild();
        Node test = suite.getFirstChild().getNextSibling().getNextSibling().getNextSibling();
        System.out.println(test);
        NamedNodeMap testName = test.getAttributes();
        Node nsdf = testName.getNamedItem("name");
        if(nsdf.getNodeValue().equals("Test localhost")){
            System.out.println("Found Element!");
        }//This actually works.

        Node loc = test.getFirstChild().getNextSibling().getNextSibling();
        System.out.println(loc);
        NamedNodeMap sdf = loc.getAttributes();
        Node as = sdf.getNamedItem("Browser");
        if(as.getNodeValue().equals("chrome")){
            System.out.println("Browser found!");
        }
       } catch (ParserConfigurationException pce) {
        pce.printStackTrace();
       }
    }
}

Answer 1

看起来像某种类型的家庭作业，所以不会给你完整的来源，但在片段之下会处理你想要改变的第一个参数。它比您尝试的解决方案更清晰，更能抵抗XML结构的变化。您可以使用它为第二个参数执行相同的操作。

XPath xp = XPathFactory.newInstance().newXPath();
Element node = (Element) xp.evaluate("//test/parameter[@name='resultLocation']", 
                    doc, XPathConstants.NODE);
node.setAttribute("name", "new attribute value");

修改xml文件中的属性

1 个答案: