Question

我需要在PostgreSQL中的一个语句中获得以下两个查询。

select count(*) as REDEEMTOTALUSED 
from voucher 
where campaign_id='123' and redeemcount>0;

select count(*) as REDEEMTOTALUNUSED 
from voucher 
where campaign_id='123' and redeemcount=0;

结果如下：

REDEEMTOTALUSED | REDEEMTOTALUNUSED
1               | 9

这可能吗？

Answer 1

请尝试：

select 
    (select count(*) as REDEEMTOTALUSED 
     from voucher 
     where campaign_id='123' and redeemcount>0) AS REDEEMTOTALUSED ,
    (select count(*) as REDEEMTOTALUNUSED 
     from voucher 
     where campaign_id='123' and redeemcount=0) AS REDEEMTOTALUNUSED

或其他方式：

    SELECT 
       SUM(CASE 
             WHEN redeemcount>0 THEN 1 
             ELSE 0 
           END) as REDEEMTOTALUSED ,
       SUM(CASE 
             WHEN redeemcount=0 THEN 1 
             ELSE 0
           END) as REDEEMTOTALUNUSED 
    from 
       voucher 
    WHERE
       campaign_id='123'

Answer 2

使用条件聚合：

select sum(case when redeemcount > 0 then 1 else 0 end) as REDEEMTOTALUSED,
       sum(case when redeemcount = 0 then 1 else 0 end) as REDEEMTOTALUNUSED
from voucher 
where campaign_id = '123';

Answer 3

SELECT count(redeemcount > 0 OR NULL) AS redeemtotalused
     , count(redeemcount = 0 OR NULL) AS redeemtotalunused
FROM   voucher
WHERE  campaign_id = '123'; -- or just 123 if campaign_id is a numeric type

适用技术概述：

For absolute performance, is SUM faster or COUNT?

除此之外：在Postgres（Overview）中，未加引号的标识符会强制转换为小写。你的语法约定在Postgres中是无用的。

Answer 4

使用CTE还有另一个选项：

with cte as (
             select count(*) as REDEEMTOTALUSED 
             from voucher 
             where campaign_id='123' and redeemcount>0
),cte1 as   (
             select count(*) as REDEEMTOTALUNUSED 
             from voucher 
             where campaign_id='123' and redeemcount=0
)
select REDEEMTOTALUSED
      ,REDEEMTOTALUNUSED
from
cte1,cte2

一个语句中的多个查询

4 个答案: