Question

我正在尝试在控制台中使用双缓冲。我已编写此代码，它编译，但在创建的控制台中，几行最下面的行填充了随机字符。改变CHAR_INFO cur[Width*Height]; 成 CHAR_INFO cur[Width*Height+200];会有所帮助，但我不明白为什么Width * Height的记忆力不够。

#include <windows.h>
#include <ctime>

#define xMax 80
#define yMax 25
#define fPS 250
#define Delay 60

class dbconsole
{
private:
    int width, height, FPS, delay;
    HANDLE h0, h1;
    CHAR_INFO *chiBuffer;
    bool curBuffer;
    int drawingTimer;
public:
    dbconsole(int Width, int Height, int fps)
    {
        CHAR_INFO cur[Width*Height];
        width = Width;
        height = Height;
        FPS = fps;
        preparebuffer(h0);
        preparebuffer(h1);
        chiBuffer = cur;
        curBuffer = 0;
        drawingTimer = clock();
    }
    void preparebuffer(HANDLE &h)
    {
        CONSOLE_CURSOR_INFO cursor;
        cursor.bVisible = false;
        cursor.dwSize = 1;
        h = CreateConsoleScreenBuffer(
                GENERIC_READ | GENERIC_WRITE,
                FILE_SHARE_READ | FILE_SHARE_WRITE,
                NULL,
                CONSOLE_TEXTMODE_BUFFER,
                NULL);
        SetConsoleCursorInfo(h, &cursor);
    }
    void putpixel(int x, int y, CHAR_INFO input)
    {
        chiBuffer[x+width*y]=input;
    }
    void depict()
    {
        SMALL_RECT srctWriteRect;
        srctWriteRect.Top = 0;
        srctWriteRect.Left = 0;
        srctWriteRect.Bottom = yMax-1;
        srctWriteRect.Right = xMax-1;
        if ((clock()-drawingTimer)*FPS>CLOCKS_PER_SEC)
        {
            if (curBuffer)
            {
                WriteConsoleOutput(h0, chiBuffer, {xMax,yMax}, {0,0}, &srctWriteRect);
                SetConsoleActiveScreenBuffer(h0);
            }
            else
            {
                WriteConsoleOutput(h1, chiBuffer, {xMax,yMax}, {0,0}, &srctWriteRect);
                SetConsoleActiveScreenBuffer(h1);
            }
            curBuffer=!curBuffer;
            drawingTimer = clock();
        }
    }
};

int main(void)
{
    dbconsole myConsole = dbconsole(xMax,yMax,fPS);
    SetConsoleTitle("Use arrow keys to control character");
    long long movetimer = clock();
    int x = 0, y = 0;
    while (true)
    {
        for (int i = 0; i < xMax; i++) for (int j = 0; j < yMax; j++) myConsole.putpixel(i,j, {' ',16});
        if ((clock()-movetimer)*Delay>CLOCKS_PER_SEC)
        {
            if (GetAsyncKeyState(VK_RIGHT))
            {
                movetimer = clock();
                if (x < xMax-1) x++;
            }
            if (GetAsyncKeyState(VK_LEFT))
            {
                movetimer = clock();
                if (x > 0) x--;
            }
            if (GetAsyncKeyState(VK_DOWN))
            {
                movetimer = clock();
                if (y < yMax-1) y++;
            }
            if (GetAsyncKeyState(VK_UP))
            {
                movetimer = clock();
                if (y > 0) y--;
            }
            if (GetAsyncKeyState(VK_ESCAPE)) return 0;
        }
        myConsole.putpixel(x,y,{1,15|16});
        myConsole.depict();
    }
}

我认为问题是由于与chiBuffer相对应的一些内存不是为它保留的，但我不明白为什么。那么，问题是什么？

Answer 1

下面：

dbconsole(int Width, int Height, int fps)
{
    CHAR_INFO cur[Width*Height];
    ....
    chiBuffer = cur;

cur是一个局部变量，一旦构造函数离开，它就不再存在了。此时，chiBuffer不再是有效指针，任何使用它都会导致未定义的行为。

一个简单的解决方案是让chiBuffer成为std::vector：

// also: #include <vector> at the top
std::vector<CHAR_INFO> chiBuffer;

并在构造函数中初始化它，如下所示：

dbconsole(int Width, int Height, int fps)
  : chiBuffer(Width * Height)
{
  // cur no longer necessary.

这需要的唯一额外更改是

//                     v----------v--- here
WriteConsoleOutput(h0, &chiBuffer[0], {xMax,yMax}, {0,0}, &srctWriteRect);

从C函数WriteConsoleOutput可以理解的向量中提取指针。这是有效的，因为std::vector保证它将元素连续存储在内存中（如数组）。

为什么在控制台中进行双缓冲时会出现随机符号？

1 个答案: